12 — nutrition& transportation in plants Flashcards

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1
Q

External features of leaf adapted for photosynthesis

A

Broad and thin lamina/ leaf blade (p: laminae):
- Increases the sa:v for maximum absorption of light energy
- Shorter diffusion distance for faster diffusion of gases into the leaf, via the stomata
- Enables light energy to reach all mesophyll cells

Network of veins:
- Veins allow transport of water and dissolved mineral salts from the roots to the mesophyll cells via xylem
- transports sucrose and amino acids from the leaves to other parts of the plant via phloem

Petiole:
- Positions lamina away from stem for maximum absorption of light energy and gaseous exchange (carbon dioxide and oxygen).
- Adaptations due to absence of petiole:
- Leaves r longer, broader lamina -> ^SAtVR
- Leaves bend at an angle away from stem

Leaves r usually arranged in a regular pattern around the stem
- ensure that leaves are not blocking one another from sunlight and that each leaf receives optimum amount of light energy

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2
Q

Waxy transparent cuticle structure + function

A

Waxy and waterproof layer above the epidermis
- Reduce excessive water loss via evaporation.

Transparent
- to allow light energy to penetrate and reach the mesophyll cells.

  • Absence of chloroplast
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3
Q

Upper/lower epidermis

A
  • UE: absence of chloroplasts
  • LE: presence of chloroplasts in guard cells
  • Single layer of closely packed epidermal cells and produce the waxy cuticle
  • both protects inner part of leaf from injury
  • Upper Epidermal cell is transparent to allow light to penetrate through the leaf to the cells and protect the inner cells from injury; [1]
  • LE contain minute openings such as stomata for gaseous exchange (carbon dioxide and oxygen) between the surrounding and the leaf cells.
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4
Q

Palisade mesophyll

A

Main site of photosynthesis
- Contains chloroplast

  • Long and cylindrical, vertically arranged n closely packed-> ^ total amt of light absorbed by chloroplasts
  • Contains the most amount of chloroplasts and is found at the top of the leaf
    • for maximum absorption of light energy for photosynthesis

Contains numerous/ many chloroplasts where chlorophyll in the chloroplasts absorb light energy and converts it to chemical energy to synthesise glucose during photosynthesis in the presence of carbon dioxide and water; [1]

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5
Q

Spongy mesophyll

A
  • Contains chloroplast
  • Irregular shaped cells, more loosely packed
  • Has numerous intercellular air spaces
    • for rapid diffusion of carbon dioxide, oxygen and water vapour inside the leaf cells
    • for water plants, this can provide buoyancy for the leaf to float on water.
  • Contain fewer number of chloroplasts than the palisade mesophyll cells
  • Has a thin film of moisture on the surface of the spongy mesophyll cells to allow carbon dioxide to dissolve first before diffusing into the cells for photosynthesis to tk place.
  • Contains vascular bundle
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6
Q

Intercellular air spaces

A
  • Mesophyll cells coated with thin film of moisture, allowing CO2 to dissolve in it b4 diffusing into mesophyll cells for photosynthesis to tk place
  • Hv large SAtVR for CO2 and O2 to quickly diffuse in n out of mesophyll cells
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7
Q

Vascular bundle

A

Contains
- Xylem – transport water and dissolved mineral salts from the roots to the leaves.
- Phloem – transports sucrose and amino acids from the leaves to other parts of the plant.

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8
Q

Guard cells

A
  • Contains chloroplast that has chlorophyll to allow photosynthesis to occur
  • Regulates the opening and closing of the stomata for gaseous exchange between surrounding and the leaf cells
  • Forms tiny openings, stomata, that’s usually absent /present in low numbers at upper epidermis: prevent excessive water loss thru evaporation
  • Controls size of stomata
  • Each stoma surrounded by guard cells
  • Cell wall near stoma is thicker
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9
Q

Desc how guard cells control movement of substances in n out of leaf/the general mechanism of stomata opening during the day. [6]

A
  • In presence of light, guard cells photosynthesise to convert light energy to chemical energy [1]
  • Forming glucose used to release energy -> pump potassium ions into cells, lowering their WP [1]
  • Net movement of water molecules from adjacent epidermal cells into guard cells via osmosis [1]
  • Cells turgid n change shape, guard cells become curved n pull open stomata. CO2 enters, O2 n water vapour exits leaf via stomata
  • (In absence of light: guard cells close stomata, restricting movement of these gases)
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10
Q

Adaptation for photosynthesis (CSCCIN)

A

Waxy, transparent cuticle on upper n lower epidermis:
- Reduces excessive water loss through evaporation from the leaf
- Transparent for light energy to penetrate and reach mesophyll cells

Stomata present in epidermal layers
- In presence of light energy, stomata (plural) opens wider to allow carbon dioxide to diffuse in and oxygen, water vapour to diffuse out of the leaf

Chloroplasts in all mesophyll cells contain chlorophyll
- Chlorophyll absorbs and convert light energy to chemical energy for synthesis of glucose during photosynthesis

More chloroplasts found at palisade mesophyll cells compared to spongy mesophyll cells
- found at the top of the leaf for maximum absorption of light energy for photosynthesis

Intercellular air spaces in spongy mesophyll
- Mesophyll cells coated with thin film of moisture, allowing CO2 to dissolve in it b4 diffusing into mesophyll cells for photosynthesis to tk place
- Hv large SAtVR for CO2 and O2 to quickly diffuse in n out of mesophyll cells

Network of veins containing xylem n phloem situated close to mesophyll cells
- - Xylem – transport water and dissolved mineral salts from the roots into the mesophyll cells
- Phloem – transport sucrose and amino acids from the leaves to other parts of the planot

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11
Q

Describe and explain how the leaf is adapted for photosynthesis [6] (Any 6)

A
  1. Petiole / leaf stalk to hold leaf in position to absorb maximum light energy [1]
  2. Thin broad lamina / leaf blade to provide short diffusion distance for gases / enables light to reach all mesophyll cells / increase surface area to volume ratio for maximum absorption of light energy. [1]
  3. Waxy cuticle to prevent excess water loss / reduces water loss through evaporation from the leaf / transparent for light to enter the leaf. [1]
  4. Stomata present in epidermal layers/lower epidermis to allow carbon dioxide to diffuse in and oxygen to diffuse out of the leaf. [1]
  5. Chloroplasts containing chlorophyll to absorb and transforms light energy to chemical energy used In the manufacture of sugars [1]
  6. More chloroplasts in the upper palisade tissue/in palisade mesophyll cells to absorb more light energy near the leaf surface [1]
  7. Intercellular air spaces to allow rapid diffusion of carbon dioxide / oxygen into and out of mesophyll cells [1]
  8. Veins containing xylem and phloem situated near mesophyll cells. Xylem transport water and mineral salts to mesophyll cells. Phloem transport sugars away from the leaf [1]
  9. Presence of guard cells to regulate / control the opening and closing of stomata for gaseous exchange
  10. Mesophyll cells lines with thin layer of moisture to allow gases to dissolve
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12
Q

Stoma

A
  • Open in presence of light energy
    • Glucose formed during photosynthesis (in guard cells) release Chem energy thru aerobic respiration -> pump potassium ions into guard cells via AT -> conc of potassium ions ^ , decreasing WP of cell sap in guard cells -> net movement of water molecules from adjacent epidermal cells into guard cells via osmosis -> guard cells swell, becomes turgid and curved -> pulls stoma to open wider.
    • Allows diffusion of CO2 from atmosphere into leaf thru stomata for photosynthesis to synthesise glucose
    • WV diffuses out of leaf thru stomata during transpiration -> transpiration pull in xylem to draw H2O up from roots to stems n leaves for photosynthesis to synthesise glucose for growth.
  • Close in dark
    • Potassium ions diffuse out of guard cells -> WP of cell sap in guard cells ^ -> net movement of water molecules out of guard cells by osmosis -> guard cells flaccid n stoma closes
  • Hot n sunny day:
    • Excessive water loss thru evaporation in guard cells -> flaccid, stoma close to prevent further water loss thru evaporation n diffusion
  • Gaseous exchange: CO2
    • CO2 rapidly used up for photosynthesis -> CO2 conc in leaf lower than atmospheric air -> CO2 diffuses from surrounding air thru stomata into intercellular air spaces down a CG -> dissolve in thin film of water on mesophyll cells -> diffused CO2 diffuses into chloroplasts for photosynthesis
  • Water loss:
    • There is a network of veins containing xylem and phloem at leaf. Water n dissolved mineral salts transported by xylem from roots to leaf -> move from cell to cell thru mesophyll cells
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13
Q

Describe the process of photosynthesis. [4] + [6]

A
  1. Chlorophyll in chloroplast to absorb light energy and convert to chemical energy [1]
  2. Photolysis of water to form oxygen gas and hydrogen atoms using light energy [1]
  3. Carbon dioxide diffuse through stomata down the concentration gradient from the environment into the leaf [1]
  4. Hydrogen atoms and chemical energy from photolysis is used to reduce carbon dioxide is reduced into glucose [1]

[6]:

During the light dependent stage, chlorophyll in chloroplasts in leaves absorbs light energy and converts it into chemical energy; [1]

Light energy is used to split water molecules into oxygen gas and hydrogen atoms/ ions through photolysis of water; [1]

During the light independent stage, hydrogen atoms/ ions, chemical energy and enzymes are used to reduce carbon dioxide to glucose; [1]

Carbon dioxide is obtained through diffusion into the stomata in the leaves and water is obtained from the soil through the roots, up the stem and into the leaves; [1]

Oxygen, a by-product diffuses out of the leaves via the stomata; [1]
The chemical equation for photosynthesis is
6CO2 + 6H2O C6H12O6 + 6O2 ;

Explain photosynthesis.
Light energy is trapped by chlorophyll and converted to chemical energy. Water molecules are split into oxygen and hydrogen atoms through photolysis of water and the oxygen produced is released as a by-product. Enzymes use the hydrogen atoms and chemical energy to convert carbon dioxide into glucose which can be oxidised to release energy in plants, during photosynthesis.
Carbon dioxide + water → glucose + oxygen
(Light energy and chlorophyll)

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14
Q

Outline the pathway of a carbon dioxide molecule from the time it enters the leaf until it eventually becomes part of a glucose molecule in a leaf cell. [6]

A
  1. Carbon dioxide diffuses into leaf from environment down concentration gradient [1]
  2. via the stomata and store in intercellular spaces [1]
  3. Carbon dioxide dissolve in the film of moisture on the spongy mesophyll cell [1]
  4. Dissolved carbon dioxide diffuse into the cell and into the chloroplasts. [1]
  5. Combines with hydrogen ions and chemical energy [1]
  6. to reduce into glucose during photosynthesis [1]
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15
Q

Describe and explain the concept of ‘compensation point’. [4]

A
  1. Rate of photosynthesis can vary according to light intensity which increases during the day and decreases at night. Rate of respiration stays constant throughout the day [1]
  2. Compensation point is when the rate of photosynthesis becomes equal to the rate of respiration [1]
  3. which means that the amount of oxygen given out / carbon dioxide taken in during photosynthesis is equal to the amount of oxygen taking in / carbon dioxide given out during respiration [1],
  4. thus there is no net output of oxygen / net intake of carbon dioxide via the stomata through the process of diffusion. [1]
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16
Q

Cambium function

A
  • Separates vascular tissues
  • Can divide n differentiate to form new xylem n phloem tissues -> thickens stem
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17
Q

Xylem

A
  • Long hollow tube stretching from root to leaf

Function:
- Transports water and dissolved mineral salts from the roots to the stem and leaves
- Provides mechanical support for the plant to prevent the plant from collapsing

Structure:
- Consists of many non-living lignified cells joined together at the ends to form a long hollow narrow tube ->reduces resistance to water flowing thru xylem
- (Lignin deposits in the inner walls of xylem vessels) + (Has diff patterns of lignification: annular, spiral, pitted)
- Narrow, hollow, continuous lumen with no cross walls, lacking in protoplasm to allow for faster transportation of water and dissolved mineral salts

Adaptations:
Long narrow hollow lumen, WITHOUT protoplasm and cross-walls → reduces resistance to water and dissolved mineral salts flowing through the xylem vessel → enabling faster rate of transport of water and dissolved mineral salts up the lumen of xylem vessel

INNER walls are lignified to provide the plant with mechanical support, and prevent the plant from collapsing.

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18
Q

Phloem

A

Function:
Transports sucrose and amino acids from the leaves to other parts of the plant

Structure:
- Contain sieve tube elements that has little protoplasm and a continuous column to allow for faster transportation of sucrose and amino acids [1]
- contains companion cell with a lot of mitochondria to release energy to load sucrose into the sieve tube elements. [1]

Sieve tube elements:
- Sieve tube cells/elements (STC) r elongated cells that lack nuclei n hv thin layers of cytoplasm
- Made up of many sieve tube cells joined end to end to form column with sieve plates in betw
- Sieve plates r cross-walls within sieve tube elements with many small sieve pores

Companion cells: (CC)
- Narrow, thin-walled cell with cytoplasm, nucleus and contains numerous mitochondria for aerobic respiration and AT
- Function: To allow active transport of sucrose and amino acids from the neighbouring mesophyll cells into sieve tube elements

Adaptations:
- Phloem sieve tube elements have very little protoplasm and are arranged to form a continuous column -> reduces resistance for faster rate of transport of sucrose and amino acids within the phloem.
- Presence of pores within the sieve plates -> allow faster rate of transport of sucrose and amino acids within the phloem.
- Companion cells have numerous mitochondria -> release more energy for active transport of sucrose and amino acids from the mesophyll cells into the phloem sieve tube cells.
- Every phloem sieve tube cell has an associated companion cell -> ensure survival of sieve tube cell.

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19
Q

If a sample of the phloem fluid is tested for Benedict’s Test, what do you think you will observe?

A

Benedict’s solution will remain blue because sucrose is not a reducing sugar.

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20
Q

Compare and contrast between the functions of xylem and phloem. [5]

A

Similarities:
- Xylem and phloem both transport substances/materials to different parts of the plant. [1]
- Xylem and phloem both transport substances as a dissolved solution to different parts of the plant. [1]

Differences:
- Xylem transports water and mineral salts from the roots to the leaves while phloem transports sucrose and amino acids from the leaves to other parts of the plant. [1]
- Xylem transports water and mineral salts in one direction up the plant while phloem transports sucrose and amino acids in both directions. [1]
- Xylem transports water and mineral salts by root pressure, transpiration pull and capillary action while phloem transports sucrose and amino acids by pressure flow as a result of loading sucrose into the phloem via active transport. [1]

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21
Q

Describe the adaptations of the phloem vessel in translocation of nutrients. [4]

A
  1. Sieve tube cell / element: Little protoplasm to minimise obstruction to flow [1] + Sieve tube plate with pores to facilitate efficient transport of sucrose and amino acid along the sieve tube element [1]
  2. Companion cells: Abundant mitochondria – release energy during respiration for active transport [1] of sucrose and amino acid into phloem and support sieve tube cell survival [1]
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22
Q

Organisation of vascular tissues in stems n roots similarity + differences

A

similarity:
- Presence of vascular bundle (found along spongy mesophyll)

Differences:

Stem:
- xylem and phloem are grouped together in the stem to form vascular bundles, arranged in a ring around pith(storage tissue)
- presence of cuticle
- absence of piliferous layer
- Xylem @ upper layer, phloem @ lower layer

Roots:
- xylem and phloem are not grouped together, they alternate
- Absence of cuticle
- Presence of piliferous layer for absorption of water through osmosis
- Epidermis, outermost layer of cells bears long & narrow extension of root hair -> ^SA:V of RHC for absorption of water&mineral salts

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23
Q

Root hair cell’s absorption methods

A

Diffusion, AT + osmosis

Diffusion/AT
When concentration of ions in the soil solution is higher/lower than that in the cell sap, Ions diffuse down/absorbed against the concentration gradient/(with th use of energy provided by cellular respiration in RHC).

Osmosis:
1. Each root hair grows between the soil particles.
2. A thin film of dilute solution of mineral salts surrounds each soil particle.
3. Water moves into the RHC and from cell to cell until it reaches the xylem vessels, down a CG, by osmosis. (Transpiration pull + lapillery action + root pressure)

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24
Q

Adaptations for absorption in RHCs (PMCMWP)

A
  1. Has long and narrow protrusion
    - Increases surface area to volume ratio to increase rate of absorption of water and dissolved mineral salts from soil to root hair cells.
  2. Has numerous mitochondria
    - Releases more energy from higher rate of respiration for active transport of dissolved mineral salts from soil solution to the root hair cell.
  3. Has cell membrane
    Prevents the concentrated cell sap w lower wp as compared to the soil, from leaking out
  4. Has conc cell sap with lower WP than soil solution
    - Allow net movement of water molecules into the root hair cell via osmosis, down a water potential gradient.
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25
Q

Photosynthesis definition + condition

A

Process in which light energy is absorbed by chlorophyll and converted into chemical energy for the formation of glucose synthesised from CO2 & H2O. O2 is released as by-product.

6CO2 + 6H2O —(light energy, chlorophyll)-> C6H12O6 + 6O2

Conditions
- CO2
- Chloroplasts containing chlorophyll which absorbs light energy during day
- Water n dissolved mineral salts from roots
- Temperature (suitable)
- Light energy

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26
Q

Destarching

A
  • A potted plant with variegated leaves is placed in the dark -> destarching (must be carried out b4 experiments)
    • In darkness, photosynthesis stops n enzymes in leaves convert starch to sucrose n transported to other parts of plant
    • Ensures starch is absent in leaves prior exprmt such that all starch present in leaves aft exprmts must’ve been formed during exprmt
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27
Q

Factors affecting rate of photosynthesis

A
  1. Light intensity
    - ^ LI, ^photosynthesis until a constant rate is reached. Beyond point X, the rate of photosynthesis remains the same even though light intensity is increased. Maximum rate of enzymatic activity in chloroplast is reached (saturation)
  2. CO2 concentration
    - ^CO2 conc, ^photosynthesis, ^glucose produced, until a constant rate is rched.
  3. Temperature
    - ^tempt to optimum, ^photosynthesis. ^T beyond optimum denatures enzyme -> decreasing p~
    - photosynthesis is enzyme dependent
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28
Q

Limiting factor

A

A factor that directly affects or limits a process if its quantity or concentration is altered.

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29
Q

Explain how rate of photosynthesis can be affected by:

Temperature [4]

A
  1. When the temperature is low, rate of photosynthesis is low as enzymes are inactive. [1]
  2. There is an increased in the rate of photosynthesis due to increased kinetic energy of enzymes that increase chance of successful collisions to form more enzyme substrate complex. [1]
  3. At optimum temperature, rate of photosynthesis is the highest as the enzymes are most active. [1]
  4. Beyond optimum temperature, decrease in the rate of photosynthesis enzyme is denatured due to deformed 3 dimensional shape of active site. [1]
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30
Q

Explain how rate of photosynthesis can be affected by:

Light intensity [3]

A
  1. Increase. More chlorophyll activated to convert more light energy to chemical energy [1]
  2. rate of photosynthesis increases to synthesise more glucose [1]
  3. Until optimum intensity is reached, light is no longer limiting [1]
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31
Q

Explain how rate of photosynthesis can be affected by:

Carbon dioxide concentration [3]

A
  1. Increase. Higher substrate concentration [1]; rate of photosynthesis increases to synthesize more glucose [1]
  2. Until maximum rate of reaction is reached, carbon dioxide concentration is no longer limiting [1]
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32
Q

Describe the fate of the glucose after it is synthesisd in the leaf. [4]
(Any 4)

A
  1. Excess glucose converted to starch and store in the leaf
  2. Convert into sucrose to load into phloem via active transport to transport to other parts of the plant via translocation
  3. Combine with nitrates in mineral salt to form amino acids
  4. Convert to fats to be stored
  5. Used in respiration to release energy for cellular activities
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33
Q

Translocation definition

A

The transport of manufactured food substances such as sucrose and amino acids in the phloem from leaves to all parts of plant by active transport

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34
Q

Experiments to test for translocation

A
  • The ‘ringing’ experiment
    • Phloem tissue is removed. Concentration of sucrose and amino acids above the ring increases.
    • shows that sucrose and amino acids are being translocated within the phloem (sieve tube elements).
  • Radioactive carbon isotopes
  • using aphids
35
Q

Describe how mineral salts is transported from the roots to the leaf. [6]

A
  1. Diffusion down concentration gradient from the soil into the root hair cell / active transport into the root hair cell against concentration gradient [1]
  2. Diffusion / active transport through adjacent cells into the root [1]
  3. Dissolved in solution [1] and transport up the xylem via capillary action, root pressure [1] and transpiration pull [1]
  4. Diffusion down a concentration gradient into leaf cells from xylem [1]
36
Q

How water from soil enters RHC

A
  1. Each root hair is a narrow extension of an epidermal cell that grows betw the soil particles, in close contact with the surrounding soil particles.
  2. Thin film of liquid surrounding each soil particle is a dilute solution of mineral salts.
  3. The RHC cell sap concentrated cell sap has a lower wp than the soil solution. Net movement of water molecules into the root hair by osmosis occurs thru partially permeable RHC cell membrane, ^ WP of the cell sap of the root hair cell (cell A) than that of the adjacent cell (cell B). Hence, net movement of water molecules from the root hair cell into the inner cell by osmosis.
  4. Similarly, water passes from cell to cell until the water enters the xylem vessels.
37
Q

Root pressure

A

Root pressure: a pressure resulting from the constant entry of water into the roots.

38
Q

Explain how potometer can be used to measure the rate of transpiration in a plant. [4] + suggest how the air bubble could be reset to its original position in the potometer. [1]

A
  1. Continuous flow/stream of water generates a suction force known as transpiration pull that draws water up leafy shoot;[1] It is assumed that the rate of absorption of water by the plant is equal to the rate of transpiration of the plant. [1]
  2. As the water from the potometer is taken up by the plant, the air bubble moves to the left in the DIRECTION towards the plant. [1]
  3. By measuring the distance moved by the air bubble per unit time[1], we can measure the rate of water loss from the leafy shoot. [1]

Open the tap to allow water to flow from the reservoir into the capillary tube to push air bubble to the right (away from plant) [1]

39
Q

Describe how a molecule of water is transported from the roots to the leaf. [6]

A
  1. Net movement of water molecule from the soil into the root hair cell down water potential gradient [1] via osmosis [1]
  2. Net movement of water molecule via osmosis through adjacent cells down the water potential gradient into the root [1]
  3. Transport up the xylem [1] via capillary action, root pressure and transpiration pull [1]
  4. Net movement of water molecule via osmosis into leaf cells from xylem [1]
40
Q

Transpiration definition

A

Loss of water vapour from the aerial parts of the plant, mainly through the stomata of the leaves, to the surrounding air, by diffusion.

41
Q

Importance of transpiration

A
  • Transpirational pull is a major suction force for moving H2O n dissolved mineral salts up xylem from roots to stem n leaves
  • H2O required as raw material at leaves for p~. Turgidity of plant maintained as H2O, lost from aerial portions of plant, is replaced. Turgid cells keep leaves spread out widely for photosynthesis.
  • Evaporation of H2O from surface of cells in leaves helps to cool plant.
42
Q

Transpiration pull (TP)

A

the suction force caused by transpiration, which results in water to move up the xylem.

43
Q

Describe how transpiration pull us formed

A
  1. Water from the thin film of moisture surrounding the mesophyll cells, evaporates to form water vapour in the intercellular air spaces. The higher concentration of water vapour accumulates in the air spaces near the stomata.
  2. Water vapour diffuses out of the stomata into the environment down a concentration gradient, decreasing the cell sap’s water potential hence water moves from xylem vessels in leaves to replace water lost in mesophyll cells.
  3. This produces a suction force, transpiration pull, that pulls the column of water in the xylem vessels up from roots to leavesF
44
Q

Explain how wind intensity will affect rate of transpiration. [4]

A
  • In moving air, the rate of water loss from the shoot is greater than in still air. [1]
  • The movement of air removes water vapour around the leaf [1].
  • This sets up a steeper concentration gradient of water vapour between the intercellular spaces of the leaf and the atmosphere [1]
  • increasing the rate of diffusion of water vapour out of the stomata of the leaves into the surrounding air down the concentration gradient. [1]
45
Q

Explain how increasing temperature will affect rate of transpiration. [3]

A
  • Increase in temperature increases the rate of evaporation of water from the moisture on mesophyll cell into the intercellular spaces. [1]
  • This increases the concentration of water vapour and causing steeper concentration gradient of water vapour between the intercellular spaces of the leaf and the atmosphere.[1]
  • This increases the rate of diffusion of water vapour out of the leaf into the air[1],
  • thus rate of transpiration increases. [1]
46
Q

Wilting

A

Occurs when rate of water VAPOUR loss through transpiration in plants is greater than the rate of water absorption by the root hair cells.

47
Q

Causes of wilting

A
  • ^^light intensity
  • ^^heat
  • ^^fertiliser that lowers wp below that of root cells -> water leaving roots
48
Q

Advantages and disadvantages of wilting

A
  • Advantages
    • Reduced leaf SA + flaccid guard cells close stomata -> Decreasing rate of transpiration
    • Prevents excessive water loss
    • Enables cooling of plant
  • Disadvantages
    • Causes stomata to close→ decreasing intake of carbon dioxide→rate of photosynthesis decreases.
    • Leaves’ exposed surface area will be reduced→decreases absorption of light energy → rate of photosynthesis decreases.
49
Q

Process of wilting

A
  1. Usually, mesophyll cells of leaf r turgid -> leaves kept firm & spread widely + turgidity keeps plant upright for max SA to reach for max sunlight
  2. Due to a net loss of water to the plant, central vacuoles of cells shrink, mesophyll cells lose turgid pressure -> flaccid -> results in wilting
50
Q

Describe and explain the advantage and disadvantage of wilting in plants. [4]

A

Definition of wilting
- Wilting is due to excessive water loss in plants via transpiration. It is the net water loss as the rate of transpiration is higher than rate of water absorption from the roots [1]
Advantages
- Reduce excessive water loss through transpiration [1] by reducing surface area of leaf and closure of stomata [1]
Disadvantages
- Reduced rate of photosynthesis [1] due to reduced surface area of leaf thus less light absorbed by chlorophyll [1] OR closure of stomata to reduce taking in of carbon dioxide as raw material for photo [1]

51
Q

Describe how the radioactive carbon dioxide in the atmosphere absorbed via photosynthesis by a plant can be found in the soil. [6]

A
  • Radioactive carbon dioxide diffuse into leaf from outside environment down concentration gradient via the stomata and store in intercellular spaces [1]
  • Combines with hydrogen ions and chemical energy to reduce into glucose during photosynthesis [1]
  • Radioactive glucose convert to sucrose and load into phloem via active transport during translocation [1]
  • Transport via phloem down the plant to the roots [1]
  • Radioactive sucrose diffuse out of phloem into root cells and convert to glucose. [1]
  • Glucose is oxidised during aerobic respiration to release energy for cellular activities and waste products radioactive carbon dioxide and water is released into the soil. [1]
52
Q

Adaptations of plants in hot climates

A
  1. May have stomata that r sunken in pits and have hairs near the stomata -> traps water vapour, increasing humidity around stomata, decreasing transpiration rate
  2. Curled/rolled leaf structure, which increases humidity around stomata
  3. May have few leaves, reducing total SA that water can diffuse out of
  4. Leaves may have a thick cuticle to further reduce water loss via evaporation thru the upper n lower epidermis
  5. May have succulent/thick and fleshy leaves that can store water in case of drought
53
Q

Explain why there r usually more stomata on the lower surface of a leaf

A
  1. As the lower surface is not directly exposed to sunlight, tempt is lower hence transpiration is lower.
  2. Water vapour can accumulate under leaves, increasing humidity around stomata, decreasing transpiration rate, thus preventing the plant from losing too much water.
54
Q

Explain how humidity affects the rate of transpiration

A

As light intensity increases, guard cells become turgid and open the stomata, allowing water vapour to diffuse out of the leaf faster, increasing transpiration rate.

55
Q

Explain how tempt affects the rate of transpiration

A

As tempt increases, ke of water molecules increases. The thin film of moisture lining mesophyll cells evaporates faster into intercellular air spaces, more water vapour diffuses out of stomata, increasing transpiration rate.

56
Q

Suggest the function of the spongy mesophyll cell shown in a water lily [1]

A

It keeps the leaf afloat on the surface of water

57
Q

State a reason for the position of the palisade cells within the lead [1]

A

Found directly under the upper epidermis, they can absorb as much sunlight as possible for photosynthesis.

58
Q

State the role of chlorophyll in photosynthesis

A

Light energy is trapped by chlorophyll and converted to chemical energy. Water molecules r split into oxygen and hydrogen atoms and the oxygen produced is released as a by-product. Enzymes use the hydrogen atoms and chemical energy to convert carbon dioxide into glucose which can be oxidised to release energy in plants.

59
Q

The stomata of most plants stay open in daylight. Explain why having stomata open in daylight is an advantage to plants. [4]

A

Keeping stomata open in daylight facilitates gaseous exchange, allowing more CO2 to diffuse into the leaf. Thus, increasing rate of photosynthesis to produce glucose in presence of light. [1]

Oxygen gas produced during photosynthesis can also diffuse out of the leaf through the stomata into the surrounding atmospheric air, which is essential for the survival of organisms to carry out aerobic respiration, releasing energy for cellular activities. [1]

Opening of stomata leads to increased transpiration rate as water vapour in intercellular air spaces can diffuse out of the leaf via stomata into surrounding air. [1]

Hence, a transpiration pull is generated in the xylem, enabling water to be transported from the roots up the xylem to other parts of the plant such as stems and leaves, keeping plant cells turgid and for plant to remain upright to capture sunlight for photosynthesis to synthesise glucose for growth. [1]

60
Q

Chloplasts can move within individual cells. A plant is placed in low light intensity. Suggest what will happen to the distribution of chloroplasts in its leaf cells. Eya. [3]

A

Chlorophyll in the chloroplasts absorbs light energy and converts
it to chemical energy to synthesise glucose during photosynthesis. [1]
The chloroplasts would move within the cytoplasm of the cell, concentrate and be packed closely together without overlapping [1] at the region with penetration of maximum light energy [1] to allow maximum absorption of light energy for photosynthesis.

61
Q

Describe and explain the change in CO2 concentration from morning to noon. [4]

A

Betw x to y time (morning to noon) -> CO2 concentration in air above rice field decreases (from to). During photosynthesis, CO2 and water r converted to sugar and oxygen in presence of light by plants.
An increase in light intensity causes more CO2 to be taken in by plant for increased rate of photosynthesis until max rate of photosynthesis is reached. Thus, CO2 conc decreases.

62
Q

Suggest one way of measuring the growth rate of trees

A

Measuring height of tree
Measuring diameter of tree trunk
Measure the girth of tree

63
Q

Suggest why light is a major factor affecting growth rate of trees [2]

A

The trees can only carry out photosynthesis in the presence of light. Photosynthesis is a process where light energy is trapped by chlorophyll to convert light energy to chemical energy stored in glucose. Glucose can be oxidised to release energy for aerobic respiration and cellular activities that r essential for growth. The amount of light affects the amount of glucose produced and thus affects the growth rate of trees.

64
Q

Explain why the rate of photosynthesis is faster on a warm day than on a cold day [4]

A

Photosynthesis process is controlled by enzymes; [1]
On a cold day when temperature is lower, enzymes are inactive and enzyme activity is lower, hence rate of photosynthesis is slower; [1]
Rate of photosynthesis is faster on a warm day with higher temperature as enzymes have more kinetic energy, increasing
frequency of effective collisions between enzymes and substrate molecules, increasing rate of formation of enzyme-substrate complexes, increasing enzyme activity; [1]
Temperature is a limiting factor of photosynthesis; [1]

65
Q

Explain why there is no overall increase in biomass of the living plant despite more glucose r formed from photosynthesis [4]

A

The average rate of photosynthesis over 24hours is similar to the average rate of respiration over 24hrs.
Thus, glucose that is produced via photosynthesis in the plant will be used for aerobic respiration to release energy needed for the plant. Since there is no excess glucose available to be converted to starch, there will be no overall increase in mass of the plant.

66
Q

State the functions + adaptations of root hairs [2]

A

Root hairs absorb water and mineral salts from surroundings for the plant. They contain high amounts of mineral salts in their vacuoles and constantly maintain a low water potential relative to the surroundings, so that water can constantly move into them thru osmosis, they also carry out active transport to absorb mineral salts from the surroundings.

They have elongated and narrow protrusions that extends into the soil to absorb water and mineral salt, increasing SA:V of cells so water and mineral salts can diffuse quickly into the cells. They have thin cell walls to allow faster absorption and a large central vacuole to absorb the max amount of water.

67
Q

Suggest which plant would lose the most mass. [2]

A

Plant x as it has more leaves than plant y, thus plant x has a higher diffusion rate of water vapour out to the surroundings through the higher number of stomata found on leaves of x, during transpiration
Plant x has a higher transpiration rate than plant y because the air surrounding plant x is less humid as x is enclosed in a plastic bag but D is exposed to air.

68
Q

Suggest why the roots of the plants were enclosed in plastic bags [1]

A

To ensure that the loss in mass in each plant is only due to transpiration from the leaves and not due to evaporation of water from moist soil.

69
Q

State the name of substance which was taken in by the aphids from the plant [1]

A

Sucrose

70
Q

Explain how water moves in the leaf from spongy mesophyll cells and out of the stomata [5]

A

Water potential in the xylem vessel is higher than the mesophyll cell adjacent to the xylem vessel, water molecules move from the xylem vessel into the adjacent mesophyll cell via osmosis, thru the partially permeable cell surface membrane. Water molecules then move into the spongy mesophyll cells down a water potential gradient via osmosis. Some of the water moves out of the spongy mesophyll cells to form a thin film of moisture over the cell surface and evaporates to form water vapour and moves into intercellular air spaces near the stomata. Water vapour the diffuses out of the intercellular air spaces via the stomata to the surroundings.

71
Q

Compare the processes for movement of water and carbon dioxide into the cytoplasm of the cell [3]

A

Similarity:
Movement of both water molecules and carbon dioxide molecules do not require energy. They are passive processes. [1]

Movement of both water molecules and carbon dioxide molecules require movement across the cell surface membrane and cell wall. [1]

Difference:
Net movement of water molecules from leaf cells of higher water potential to leaf cells of lower potential by osmosis down a water potential gradient but carbon dioxide molecules move by diffusion down the concentration gradient from a region of higher carbon dioxide concentration, ie. intercellular air spaces to a region of lower carbon dioxide concentration, ie. the chloroplasts in the leaf cells. [1]

Marker’s report: Need to include movement across the cell surface membrane and cell wall

72
Q

Explain how environmental factors affect transpiration [4]

A

Transpiration is affected by wind, temperature, humidity and light intensity.

Wind removes water vapour and reduces the concentration of water vapour around the leaf, making the water vapour concentration gradient between the leaf and atmosphere steeper, increasing the rate of diffusion of water vapour out of the stomata of the leaves. Rate of transpiration increases. [1]
The higher the temperature, the faster the water evaporates into intercellular spaces, which causes a steeper water vapour concentration gradient between the leaf and atmosphere, increasing the rate of diffusion of water vapour out of the stomata of the leaves. Rate of transpiration increases. [1]
Increasing humidity increases the concentration of water vapour in the atmosphere, making the water vapour concentration gradient between the leaf and atmosphere less steep; hence decreasing the rate of diffusion of water vapour out of the stomata of the leaves. Rate of transpiration decreases. [1]
Stomata open wider under higher light intensity. Faster rate of diffusion of water vapour out of the leaf. Rate of transpiration increases.[1]

73
Q

Bryophytes are a group of land plants which are unable to produce xylem. Suggest one feature in the external appearance of these plants and explain your answer. [2]

A

Short. [1] Lignin is not present to hold the plant upright. [1]
Thin leaves. [1] Xylem absent, hence depends on osmosis for water transport. [1]

74
Q

Explain why radioactivity was detected at the stem when the plant was exposed to radioactive CO2 for 5 hours. [4]

A

CO2 diffuses via the stomata.[1]
CO2 is reduced / converted to glucose during photosynthesis. [1]
Glucose will be converted to sucrose [1]
and translocated to point X via phloem. [1]
(If in soil:
Sucrose respiration/ oxidation to carbon dioxide [1]
Diffuses into soil [1]

75
Q

What is the purpose of boiling the leaf first before using it to test for photosynthesis. [1]

A

To kill the leaf and stop all chemical reactions (especially respiration that uses up
stored starch in leaves). [1]

76
Q

To destarch, a leaf is boiled first and put into a solution. Name that solution and its function. [1]
After which, the leaf is placed in water bath. Explain the purpose of this step. [1]

A
  1. Ethanol. To remove chlorophyll.
  2. To soften the leaf
77
Q

Describe and explain the importance of vascular bundles in a plant; [3]

A

Xylem has lignified walls for mechanical support [1]
Xylem allows transport of water and dissolved
mineral salts [1]
Phloem allows transport of sucrose from leaves to
all parts of plant [1]

78
Q

Describe how light energy is converted to chemical energy and stored in carbohydrates in plants [4]

A

Light energy is absorbed by chlorophyll and converted to
chemical energy.[1] Light energy is used to split water
molecules into oxygen gas and hydrogen atoms/ ions
through photolysis of water. [1]
During the light independent stage, hydrogen atoms/ ions,
chemical energy and enzymes are used to reduce carbon
dioxide to glucose [1] during photosynthesis. [1]
Carbon dioxide + water → glucose + oxygen
Light energy and chlorophyll

79
Q

Suggest how conditions in a glasshouse can be controlled to ensure max growth of plants [5]

A

Optimum levels + of factors/conditions such as carbon dioxide/ temperature / water/ light/ nutrients/ pH of soil/ humidity [3]
+ 2 control methods; thermostats for temperature/ hose/
sprinklers for water/ turn on lights for light (must show link) [2]

Conditions in a glasshouse such as light intensity, temperature, amount of carbon dioxide, amount of water, concentration of mineral salts in soil and soil pH can be optimised to ensure the maximum growth of plants. A computerised system can be used to monitor the conditions frequently so that the factors that affect the rate of photosynthesis of the plants r kept at optimal levels. Enzymes involved in photosynthesis are highly sensitive to tempt changes. More CO2 supplied can also increase rate of photosynthesis.

80
Q

Describe 2 features of the N. Oleander leaves that accounts for the decreased transpiration rate. [4]

A

N. oleander has thicker cuticle/three layers of epidermal cells; This reduces loss of water by evaporation; [1]
Stomata for N. oleander are found in crypts/pockets/concave/sunken spaces along the surface of the leaf/ stomata surrounded by hair-like structures; AW [1]
This increases humidity around the stomata, decreases steepness of concentration gradient of water vapour hence resulting in lower rates of transpiration; [1]
Reduced transpiration decreases suction force of transpiration pull in N. oleander hence causes the bubble in the potometer to move a shorter distance; [1]

81
Q

Suggest why a glass tank with water was placed between the lamp and the bottles containing algae in the investigations. [1]

A

Reduces heat effect from the lamp.
[1]

82
Q

Explain how feeding on leaf mesophyll tissue will affect tomato production. [2]

A

Less chloroplasts -> less photosynthesis rate [1]
to synthesise less glucose + lower production [1]

83
Q

State one error in the potometer set-up shown and explain its purpose. [2]

A

Opening with leafy shoot not sealed with oil on surface of liquid [1]
To prevent water from evaporating [1]

84
Q

Explain why there is a layer of oil on the surface of water in the measuring cylinder. [1]

A

To prevent water loss via evaporation from the water surface. [1]