1.2 Neurones and Bioelectric Signals Flashcards

Med Sci Lecture 2

1
Q

Cell Body (Soma)

A

metabollic centre

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2
Q

dendrites

A

input region

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3
Q

axon

A

signal propagation

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4
Q

synaptic terminals

A

signal transmission

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5
Q

Whats in the soma

A

nucleus, GA and other organelles

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6
Q

What does the soma branch out into

A

into 2 kinds of processes

  • several short dendrites
  • one long turbular axon
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7
Q

What does the soma do

A

integrates the signals received and may change the activity of the cells causing generation of an AP

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8
Q

What are dendrites

A

branch out in a tree pattern

main apparatus for receiving incoming signal from other nerve cells

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9
Q

What does the axon do

A

typically extends some distance from the soma and carries signals to other neurones

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10
Q

What is the initial segment

A

it is near the beginning of the axon where AP is initiated in a special trigger region

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11
Q

What speed does propagation happen

A

1 to 100 m/s

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12
Q

AP voltage?

A

100mV

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13
Q

Information conveyed by AP determined by…

A

pathway and frequency

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14
Q

size of axon

A

0.1mm to 2m

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15
Q

what are large axons wrapped in

A

myelin sheath interrupted by the nodes of Ranvier

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16
Q

What are synapses

A

near the end of the axon it divides in to fine branches that contact other neurons at specialised zones called synapses

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17
Q

presynaptic cell

A

nerve cell transmitting signal

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18
Q

postsynaptic cell

A

cell receiving the signal

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19
Q

presynaptic/nerve terminals

A

specialised enlarged regions of axons branches that presynaptic cells transmit signals from

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20
Q

synaptic cleft

A

very narrow space separating presynaptic and postsynaptic

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21
Q

where do the terminals end

A

Most presynaptic terminals end on the postsynaptic neuron’s dendrites; but the terminals may also terminate on the cell body or, less often, at the beginning or end of the axon of the receiving cell

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22
Q

Examples of transient electrical signals

A

receptor potentials, synaptic potentials, and action potentials

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23
Q

what causes transient electrical signals

A

temporary changes in the electric current in and out of a cell

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24
Q

what do changes in current drive

A

dives the electrical potential across the cell membrane away from its resting value

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25
A rest what is on the extracellular surface of neurons cell membrane
excess of +ve charge
26
A rest what is on the cytoplasmic surface of neurons cell membrane
excess of -ve charge
27
what does the lipid bilayer do
act as a barrier to the diffusion of ions, it acts as a resistor to the flow of ions
28
membrane potential
charge separation gives rise to a voltage across the membrane
29
membrane potential equation (Vm)
π‘‰π‘š = 𝑉𝑖𝑛 βˆ’ π‘‰π‘œπ‘’π‘‘
30
resting membrane potential (Vr)
membrane potential at rest convention π‘‰π‘œπ‘’π‘‘ = 0 so 𝑉 π‘Ÿ = 𝑉𝑖𝑛 range of -60mV to -70mV
31
what does electrical signalling involve
brief changes to this by electrical currents (of ions) across the membrane
32
direction of current
conventionally defined by net movement of +ve charge
33
cations travel...
in direction of current
34
anions travel...
away from current
35
depolarisation
reduction of charge separation (less –ve π‘‰π‘š)
36
hyperpolarisation
increase in charge separation (more –ve π‘‰π‘š)
37
electrotonic potentials
Changes in π‘‰π‘š that do not lead to opening of gates ion channels are passive responses happens for small depolarisation and most hyperpolarisations
38
When depolarisation reaches a threshold
the cell opens voltage gated-ion channels and produces an all-or-none AP
39
Potassium Ion concentrations
is about 20 times higher concentrated within the cell than outside
40
Sodium Ion concentrations
9 times higher outside than inside the cell.
41
how are charges in and out of the cell balanced
due to organic ions
42
What does the concentration gradient create
a chemical driving force
43
What do potassium ions flow through
flow through their specific ion channels in the first place is because there is a massive potassium concentration gradient between the intra- and extracellular space
44
what happens due to potassium ions leaving cell
the spare negative charges incide the cell go to the surface of the inner cell membrane shifting the electrical potential across the membrane towards more negative values
45
electrical driving force
the shift to negative values gives rise to this | Due to the capacitive properties of the membrane at its outer surface the same number of positive charges accumulate
46
what stops the outflow of potassium ions
when the electrical driving force building up in the opposite direction, as potassium ions exit the cell, is equal to the chemical driving force.
47
what does knowing the concentration of potassium ions inside and outside the cell allow us to predict
predict the potential (Ex) across the membrane at which the net flux of potassium ions become zero
48
Equation for chemical driving force
π‘Šπ΄ = 𝑅 𝑇ln [π‘‹π‘œ] [𝑋𝑖] ο‚· 𝑅 is the gas constant 8.31 𝐽 π‘šβˆ’1πΎβˆ’1 ο‚· 𝑇 is the absolute temperature in 𝐾
49
Equations for electrical driving force
π‘Šπ΅ = 𝐸π‘₯ 𝑧 𝐹 ο‚· 𝑧 is valence of ion ο‚· 𝐹 is the Faraday constant = 96500 𝐢 π‘šπ‘œπ‘™βˆ’1
50
How to find Nerst equation
equate electrical and driving force equations
51
Equation for The Nerst Equation
𝐸π‘₯ =(𝑅𝑇/𝑧𝐹) (ln ([π‘‹π‘œ] /[𝑋𝑖]))
52
Measurement for potassium cells in Gilal cells
-75mV for 𝐾+ in Glial cells which are only permeable to potassium at rest
53
Nerve cells at rest are permeable to...
Na, Cl, K
54
does K or Na have more channels
There are many more resting 𝐾+ channels than π‘π‘Ž+ channels so 𝑉 π‘Ÿ does not deviate much from 𝐸𝐾 = βˆ’75 π‘šπ‘‰ to the πΈπ‘π‘Ž = +55 π‘šπ‘‰
55
what happens when the potential begins to depolarise from the value of K+ equilibrium potential
𝐾+flux is no longer in equilibrium across the membrane.
56
what is reduction
Reduction in the negative electrical force driving 𝐾+into the cell means that there is now a net flow of 𝐾+out of the cell, tending to counteract the π‘π‘Ž+influx.
57
what happens the more the membrane potential is depolarised
the greater is the net electrochemical force driving 𝐾+out of the cell Consequently the greater the net 𝐾+efflux
58
what happens eventually after the membrane keeps depolarising
the membrane potential reaches a new resting level so the increased outward movement of 𝐾+ just balances the inward movement of π‘π‘Ž+
59
What is the Goldman Equations
π‘‰π‘š = (𝑅𝑇/𝐹)ln((𝑃k[𝐾+]π‘œ + 𝑃na[π‘π‘Ž+]π‘œ + 𝑃cl[πΆπ‘™βˆ’]π‘œ ) / (𝑃k[𝐾+]i + 𝑃na[π‘π‘Ž+]i + 𝑃cl[πΆπ‘™βˆ’]i))
60
What is the Goldman Equation for
convenient to describe the membrane potential as it allows for adding other ions species the membrane is also permeable for the ion species with the highest permeability will dominate Vm
61
lipid bilayer reflects what is an electrical circuitq
capicitance as it has the ability of an insulator to separate electrical charges on either side of it and the presence of thin layer of charge on either side causes a potential difference
62
what kind of capacitor is a membrane
leaky capacitor due to ion-channels that can conduct charge
63
ion channels are highly...
conductive
64
ion equilibrium potentials act as
batteries as can generate emf
65
each K+ channel is represented as...
resistor or conductor of ionic current with single current conductance of 𝛾k
66
what is the sodium - potassium pump
see diagram pg 20 on notes | requires energy to maintain and re-establish the intracellular ionic concentration of a cell at rest
67
Why is the pump needed just because energy is required
More active neurones have a higher demand for ATP so ADP must be phosphorylated more rapidly The process requires oxygen so clearly neural activity requires oxygen as the resting potential cannot be maintained without the pump
68
what does the pump exchange
3 Na for 2 K
69
what do we assume when calculating membrane potential using equivalent circuits
Initially ignore πΆπ‘™βˆ’ channels and begin with only 𝐾+ and π‘π‘Ž+ channels Also ignore the small influence of the π‘π‘Ž+-𝐾+ pump as it is small Consider steady-state where π‘‰π‘š is not changing so ignore membrane capacitance and its delaying effects on changes in π‘‰π‘š
70
which membrane conductance is greater
K is greater than Na
71
total pd across Na potential
π‘‰π‘š = πΈπ‘π‘Ž + (πΌπ‘π‘Ž/ π‘”π‘π‘Ž) | πΌπ‘π‘Ž = π‘”π‘π‘Ž Γ— (π‘‰π‘š βˆ’ πΈπ‘π‘Ž)
72
total pd for K potential
π‘‰π‘š = 𝐸𝐾 + (𝐼𝐾/ 𝑔𝐾) | ∴ 𝐼𝐾 = 𝑔𝐾 Γ— (π‘‰π‘š βˆ’ 𝐸𝐾)
73
what happens if Vm is greater than Ek
driving force is positive and current is outwards
74
what happens if Vm is smaller than Ek
driving force is negative and current is inwards