1 - Intro Flashcards

1
Q

How do you calculate the respiratory quotient? What is it?

A

Moles CO2 over moles O2

the ratio of the volume of carbon dioxide expelled to that of oxygen consumed by an organism, tissue, or cell in a given time.

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2
Q

How many kJ does per mole glucose does it take to produce one mole of ATP?

A

-30.5 kJ per mole glucose.

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3
Q

What makes ATP a high energy phosphate compound?

A

ATP is considered a high energy phosphate compound because the hydrolysis of its two phospoanhydride bonds proceeds with the release of a large negative ΔG*’ (standard free energy)

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4
Q

The hydrolysis of phosphocreatine to creatine and phosphate has a standard free energy of -43.1 kJ/mole. Write the individual reactions and net reaction for the coupling of phosphocreatine hydrolysis and ATP synthesis from ADP. Is the synthesis of ATP thermodynamically favoured? Why or why not?

A

Phosphocreatine + H20 -> creatine + Pi (deltaG = -43.1 kJ/mole)

ADP + Pi -> ATP + H20 (delta G = +30.5 kJ/mole)

Phosphocreatine + ADP -> creatine + ATP (delta G = -12.6 kJ/mole)

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5
Q

What is facilitated diffusion across a membrane?

A

The rate is not limited by the energy state of the cell.

(also known as facilitated transport or passive-mediated transport) is the process of spontaneous passive transport (as opposed to active transport) of molecules or ions across a biological membrane via specific transmembrane integral proteins.

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6
Q

Describe the formation of mixed micelles in the small intestine during the digestion of dietary fat. What dietary components would be decreased in a person with a defect in bile salt secretion into the gut?

A

Bile salts are cholesterol derivateives that are synthesized in the liver. Stored in the bile and released into the small intestine. In the presence of bile salts and the mechanical agitation that occurs inthe intestine, traicylglycerols in the diet are emulsified to form emulsions with the amphiphatic bile salts at the triacylglycerol-water interface. Triacylglycerol lipase and other lipases act on the droplet at the interface to hydrolyze the fatty acid componentns of the traicyglycerol. These fatty acids are also amphipathic and are incorporated into the micelle surface. Forming a mixed micelle. A person with a defect in bile salt secretion would be unable to form micelles efficiently and would therfefore have inefficient digestion and absorption of fats from the diet. In addition, the absorption of the fat soluble vitamins (A, E, D, K)

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7
Q

How can you determine the rate determining step by thermodynamic criteria?

A

Often early in the pathway, the RLS has a very high negative ΔG*’, indicating its irreversibility.

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8
Q

What is the rate determining step in glycolysis?

A

The phosphofructokinase reaction that converts fructose-6-phosphate to fructose-1,6-bisphosphate

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9
Q

What is the rationale for the unusual regulation of glycolysis?

A
  • The first reaction in glycolysis is catalysed by hexokinase (AKA glucokinase), this is not a suitable control point for the overall pathway of glycolysis because significant amounts of sugar ENTER the pathway as glucose-6-phosphate, the product of the hexokinase reaction. For example, galactose is converted to glucose-6-phosphate to enter glycolysis. In addition, mannose and fructose enter glycolysis as fructose-6-phosphate.

Therefore the phosphofructokinase reaction is the most effective point for regulation of glycolysis as it is the first committed step in the pathway.

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10
Q

What enzymes do the brain and muscle tissues lack that precludes the secretion of glucose derived from glycogen?

Which tissue does contain this enzyme and in which organelle?

A

glucose-6-phosphatase

Glucose 6-phosphatase is an enzyme that hydrolyzes glucose-6-phosphate, resulting in the creation of a phosphate group and free glucose. Glucose is then exported from the cell via glucose transporter membrane proteins. This catalysis completes the final step in gluconeogenesis and glycogenolysis and therefore plays a key role in the homeostatic regulation of blood glucose levels.

Liver, in the endoplasmic reticulum.

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11
Q

What is the metabolic advantage to breaking down glycogen to phosphoglucose (phosphorolysis) rather than glucose (hydrolysis)?

A

Phosphorolysis saves energy expenditure by producing glucose-1-phosphate instead of glucose. The energy required to convert glucose to glucose-6-phosphate via hexokinase (eses ATP) is avoided by phosphorolysis

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12
Q

UDP-glucose pyrophosphorylase catalyses the synthesis of UDP-glucose in the glycogen biosynthetic pathway.

The ΔG*’ for the reaction is near zero. Where does the energy to drive the reaction to UDP-glucose come from?

A

The energy to drive this reaction is obtained from the hydrolysis of pyrophosphate by the ubiquitous enzyme pyrophosphatase (ΔG*’ = -33.5 kJ/mole)

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13
Q

UDP-glucose pyrophosphorylase catalyses the synthesis of UDP-glucose in the glycogen biosynthetic pathway.

[γ32P]UTP was used as a tracer to monitor the reaction in hepatocytes. Where is the radioactivity at the completion of the reaction?

A

This enzyme converts glucose-1-phosphate to uridine diphosphate (UDP)-glucose, which is the step before glycogen synthase and branching enzyme.

A by product of this reaction is pyrophosphate (from the hydrolysis of UTP to UDP - by attaching uridine and the alpha phosphate to the already phosphorylated glucose). Pyrophosphate (the leaving beta and gamma phosphates) is then converted by pyrophosphatase to inorganic phosphate.

The radioactivity will be found in inorganic phosphate after completion of the reaction.

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14
Q

The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If acetyl-CoA is labeled with 14C at the carbonyl carbon, how many rounds of the cycle are required before 14CO2 is released?

A
  • Acetyl from Acetyl-CoA becomes the terminal (C4) carbon of succinyl-CoA (which becomes succinate, a symmetrical 4 carbon diprotic dicarboxylic acid from alpha-ketoglutarate).
  • Succinate becomes fumerate, fumerate becomes malate and malate becomes oxaloacetate.. Because succinate is symmetrical, the oxaloacetate can have the label at C1 or C4.
  • When these condense with acetyl-CoA to begin the second round of the cyle, both of these carbons are eliminated as CO2 during the isocitrate dehydrogenase and alpha-ketoglutarate dehydrogenase reactions (formation of alpha ketoglutarate and succinyl-CoA respectively).

So in short, 14 CO2 will be released in the second turn of the cycle.

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15
Q

Although animals cannot synthesize glucose from acetyl-CoA, if a rat is fed 14C-labeled acetate, some of the label appears in glycogen extracted from its muscles. Explain.

A

Animals cannot carry out the net synthesis of glucose from acetyl-CoA (which is the fate of fed acetate). However, 14C labeled acetyl-CoA enters the citric acid cycle and is converted to oxaloacetate.

Some of this oxaloacetate may be converted to glucose via gluconeogenesis and converted to glycogen by muscle.

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16
Q

List four dehydrogenase reactions coupled to the reduction of NAD+ to NADH

Which one is conspicuously not? Why?

A
  • Pyruvate dehydrogenase
  • GLycerol-3-phosphate dehydrogenase
  • Isocitrate dehydrogenase
  • Malate dehydrogenase

Succinate dehydrogenase is not coupled to to the reduction of NAD+ because NAD+ does not have enough reducing power, FAD is needed.

17
Q

Show the net reaction for the coupling of FADH2 oxidation (E = -0.04) to coenzyme Q reduction (E = 0.045) in the electron transport chain.

Calculate the free energy yield (Delta G) from the net reaction. Does this redox couple release sufficient energy to synthesize ATP from ADP and Pi? Explain?

A

FADH2 -> FAD + 2H+ (E = -0.04)

CoQ (ox) + 2H+ -> CoQ (red) (E = 0.045)

FADH2 + CoQ (ox) -> FAD + CoQH2 (red)

ΔG* = nFΔE*’ = -2(96.5)(+0.045 -(-0.04) = -16.4 kJ/mole

1 mole ATP requires -30.5 kJ/mole of energy, therefore this couple is not sufficient for ATP synthesis

18
Q

Rotenone, a toxic natural product from plants, strongly inhinits NADH dehydrogenase of insect and fish mitochondria. Antimycin A, a toxic antibiotic, strongly inhibits the oxidation of ubiquinol. Why is rotenone ingestion lethal to some insect and fish species?

Why is antimycin A a poison? Assuming that both of these compounds are equally effective at blocking their respective sites in the electron transport chain, which would be the more potent poison and why?

A

Inhibition of NADH dehydrogenase by rotenone decreases the rate of electron flow through the respiratory chain and decreaes ATP production. If the ATP production is not sufficient to meet the requirements of the organism, it will die.

Antimycin A inhibits the oxidatio nof coenzyme Q (ubiquinol) and reduces electron transport beyond this point in the respiratory chain. If this is sufficent to reduct ATP production below the level required to meet the needso f the organism, it will also die.

SInce antimycin A blocks all electron flow to oxgen, whereas rotenone only blocks flow from NADH (and allows FADH2 electron to continue to enter the respiratory chain) the former is a more potent poison.

19
Q

Isocitrate dehydrogenase is found only in the mitochondrion, but malate dehydrogenase is found in both the cytosol and the mitochondrion. What is the role of the cytosolic malate dehydrogenase?

A

Cytosolic malate dehydrogenase plays a key role in the transport of reducing equivalents across the inner mitochondrial membrane via the malate-aspartate shuttle.

20
Q

Under aerobic conditions, extramitochondrial NADH must be oxidized by the mitochondrial electron transfer chain. Consider a prep of rat hepatocytes containing mitochondria and all the cytosolic enzymes.

If radioactive NADH (labelled hydrogen) is introduced, radioactivity soon appeasr in the mitochondrial matrix. However labelled carbon in NADH does not have the same effect. Why?

A

The inner mitochondrial membrane is impermeable to NADH, but the reducing equivalents are transferred through the membrane indirectly. The labelled hydrogen atoms from cytosolic NADH are used to reduce oxaloacetate to malate in the cytosol and transported to the mitochondrial matrix. The radioactive malate is the re-oxidized to oxaloacetate and the labelled hydrogen is used to reduce matrix NAD+ to NADH.

In contrast, the labelled carbon in the ring of NADH never leaves the cytosol.

21
Q

When exposed to an atmosphere of radioactive CO2 (14-C), the C is incorporated into bicarbonate and used for synthesis of malonyl-CoA from acetyl-CoA. What enzyme catalyses the synthesis of malonyl-CoA from acetyl CoA? On what carbon atoms does the 14-C appear in palmitate?

A

Enzyme: acetyl-CoA carboxylase

None of the 14-CO2 appears in the product, palmitate because it is released during the condensation reaction catalysed by the β-ketoacyl ACP synthase.

22
Q

A rat liver cytosol preparation is supplemented with 14C acetate to study the incorporation of the acetate methyl carbon ito palmitic acid. On which carbon atoms will 14-C appear?

A

All of the even numbered carbons in palmitate will be labeled with 14-C.

23
Q

What enzymes are required for the biosynthesis of linoleic acid (a polyunsaturated fatty acid)?

A
  • Acetyl-CoA carboxylase
  • β-ketoacyl-CoA reductase
  • Δ12 desaturase
  • Δ9 desaturase
24
Q

True or false, fatty acid synthase is required for the biosynthesis of linoleic acid (a polyunsaturated fatty acid).

A

false

25
Q

2-bromopalmitoyl-CoA inhibits the oxidation of palmitoyl-CoA by isolated mitochondria, but has no effect on the oxidation of palmitoylcarnitine. What is the most likely site at which 2-bromopalmitoyl-CoA inhibits fatty acid oxidatoin?

A

2-bromopalmitoyl-CoA inhibits carnitine acyltransferase ( (CATI) but does not inhibit CATI. Therefore, palmitoylcarnitine provided exogenously can use the carnitine transporter to cross into the mitochondrial matrix and be converted back to palmitoyl-CoA by the CATII for oxidation.

26
Q

Explain why malonyl-CoA inhibits the oxidation of palmitic acid by isolated mitochondria but has no effect on the oxidation of octanoic acid

A

Malonyl-CoA inhibits CATI and consequently the oxidation of palmitic acid (C15:0). It has no effect on the oxidation of octanoate (C8:0) because short chain and medium chain fatty acids can enter the mitochondrial matrix directly where they are activated by short-chain or medium-chain acyl-CoA synthetase.

27
Q

What is intermediary metabolism?

A

All processes involved in the generation and storage or utilization of energy (does not involve nucleic acid)

28
Q

What is the point of the citric acid cycle and what does it absolutely need?

A

Absolutely needs oxygen, only aerobes can do it.

It is the oxidation of pyruvate (product of glycolysis) to CO2, with the generation of reduced electron carriers being the main goal.

These reduced electron carriers are oxidized in the electron transport chain to generate ATP by oxidative phosphorylation

29
Q

Exergonic or endergonic, which require energy and which produce it?

A

Exergonic: produce energy (favourable)

Endergonic: need energy (unfavourable). Coupled to exergonic reactions so that they proceed.

Energy is gained by oxidizing organic substrates with reduction of electron carriers (eg. NAD+), which is subsequently reoxidized in the mitochondria

30
Q

What determines caloric content?

A

The more highly reduced a substrate, the more energy is released during oxidation.

Fat is highly reduced and therefore calorically dense.

The respiratory quotient is lower for fat than carbohydrates (require more oxygen to oxidize)

31
Q

Give the free energy for the hydrolysis of the following phosphates

ATP to AMP and pyrophosphate

ATP to ADP and inorganic phosphate

Pyrophosphate to inorganic phosphate

A

ATP to AMP and pyrophosphate: -45.6

ATP to ADP and inorganic phosphate: -30.5

Pyrophosphate to inorganic phosphate: -19.2

32
Q

What is adenylate charge and how is it measured?

A

THe measure of the number of phosphoanhydride bonds in a cell. Can be a measure of healthy cells and proper energy status

AC = ([ATP] + 0.5[ADP]) / {ATP + ADP + AMP]