1 Fluid Properties

Question 1

Newton’s Law of Viscosity

Answer 1

Shear stress τ is directly prop to Θ/t rate of shear strain

τ= μ(du/dy)
Where μ is constant dynamic velocity (for newtonian fluids)

Question 1

Kinematic viscosity

Answer 1

μ/p

Question 2

Θ/t = u/y

Answer 2

Θ/t = x/yt = ut/yt = u/y

Question 3

What if velocity variation in y direction is linear

Answer 3

u-y graph is straight and not a curved parabola

du/dy=u/y

Question 4

Non slip condition

Answer 4

at bottom surface when y=0, u=0

Question 5

Solid VS Fluid shear strain

Answer 5

Solid: shear strain τ magnitude Φ

Fluid: shear strain τ RATE Φ/t

Question 6

X and Y components of a resultant F on a plane

Answer 6

X (tangential) is shear stress τ

Y (normal) is pressure P

Question 7

Continuum conditions (average of fluid quantities taken)

Answer 7

Order of point dimension must be a lot smaller than the system dimension and a lot larger than the distance between molecules

Question 8

Specific Vol Vs

Answer 8

Vs=1/p

Question 9

Specific Weight gamma

Answer 9

pg

Question 10

Specific gravity s

Answer 10

p/Pwater

Question 12

Unit of dynamic viscosity

Answer 12

μ

kg/ms
OR
Ns/m2

Question 13

Unit of Kinematic Viscosity

Answer 13

v

m2/s

Question 14

Specific gravity s unit

Answer 14

no units

Question 15

Specific density units

Answer 15

P

kg.m3

Question 16

Bulk Modulus

Answer 16

K

N/m2

Question 17

Fluid viscosity unit

Answer 17

μ

Ns/m2

Question 18

du/dy unit

Answer 18

m/s/m

Question 19

Shear stress unit

Answer 19

τ

N/m2

Question 20

SG

Answer 20

P substnace/P water

Question 21

Bulk mod k

Answer 21

Pressure needed per percentage in vol
K=-dP/ dV or V)
K=dP/ (dp or p)

Question 22

Unit of bulk mod k

Answer 22

N/m2

Question 24

capillary action

Answer 24

Vol(SW gamma)=Circumference(surface tension sigma)(cos theta)