1. Cellular & Molecular Structure & Function Flashcards

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1
Q

Why are we interested in understanding macromolecular structure?

A

It is the basis of biological structure and function.

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2
Q

What is the most common way of determining 3D protein structure?

A

X-ray crystallography

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3
Q

What is the general clinical importance of GPCRs?

[Clinical extra info]

A
  • 6 of the top 10 and 60 of the top 200 best-selling drugs in the US in 2010 target GPCR
  • This is because there are over 375 GPCRs encoded by the human genome, of which 225 have known ligands
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4
Q

What are the two main types of biophysical techniques that can be used to study proteins?

[Experimental extra info]

A
  • Spectroscopic -> Study the environment of various atoms to deduce structural information
    • CD, UV
    • Fourier transform infrared
    • NMR
    • X-ray absorption fine spectrum
  • Scattering -> Form an image of the species under study
    • Dynamic laser light scattering
    • Microscopy
    • Neutron scattering
    • Small-angle X-ray scattering
    • X-ray diffraction
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5
Q

Why are X-rays ideal for studying macromolecular structure?

[Experimental extra info]

A

The wavelength of X-rays is similar to the size of atoms, which is what we want to study.

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6
Q

Describe briefly the process of X-ray crystallography.

[Experimental extra info]

A
  • Purification
  • Cystallisation
  • Data collection (via diffracting X-rays using the crystal)
  • Map calculation
  • Map interpretation
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7
Q

What are some of the different types of electron microscopy used in studying proteins and why is each useful?

[Experimental extra info]

A
  • Single particle cryo-EM -> Allows large macromolecules to be imaged that cannot otherwise be crystallised
  • Cryo-electron tomography -> Allows images to be obtained of cells and their machinery
  • Correlative light (fluoresence) and electron microscopy (CLEM) -> Allows for multicolour labelling and Angstrom range resolution of cellular components
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8
Q

Give some examples of macromolecules and what they are made from.

A
  • Proteins -> Made from amino acids
  • Polysaccharides -> Made from monosaccharides
  • Nucleic acids -> Made from nucleotides
  • Fats -> Made from fatty acids
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9
Q

What type of reaction is the formation of macromolecules usually?

A

Condensation (or dehydration)

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10
Q

Draw the formation of a peptide bond, noting the functional groups involved.

A
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11
Q

Draw the formation of an ester bond, noting the functional groups involved.

A
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12
Q

Draw the formation of a glycosidic bond, noting the functional groups involved.

A
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13
Q

What is another name for a glycosidic bond?

A

Ether bond

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14
Q

Describe the different levels of protein structure and the interactions at each level.

A
  • Primary -> The order of amino acids in sequence -> Covalent bonding (i.e. peptide bonds)
  • Secondary -> The regular folding into an alpha helix or beta pleated sheet -> Repetitive hydrogen bonding
  • Tertiary -> The more complex forlding of regular structures -> Hydrophobic effect, ionic, disulfide, Van der Waal’s forces, hydrogen bonding
  • Quaternary -> The interaction of multiple structured polypeptides (and non-protein components) -> Hydrophobic, ionic, disulfide, Van der Waal’s forces, hydrogen bonding
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15
Q

Draw the general structure of an amino acid.

A
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16
Q

What are the two carbons in an amino acid called?

A
  • The ‘central’ carbon (the one with the R group attached) is called the alpha carbon
  • The carbon in the carboxyl group is just a carbon atom
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17
Q

Which functional groups in an amino acid are involved in peptide bonds?

A

COO- and NH3+

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18
Q

How many commonly encountered amino acids are there?

A

20

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19
Q

Does the charge of an amino acid ever change?

A

Yes, it varies depending on the pH.

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20
Q

Describe the charges of an amino acid at different pHs.

A
  • Physiological pH -> Both sides of the amino acid have a charge (NH3+ and COO-)
  • Low pH -> Only NH3+ side is charged (i.e. both sides are protonated)
  • High pH -> Only COO- side is charged (i.e. both sides are deprotonated)
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21
Q

What are the main functional types of amino acid side group?

A
  • Charged -> Acidic and basic
  • Uncharged polar (hydrophilic)
  • Uncharged non-polar (hydrophilic)
  • Special cases / Structural
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22
Q

Draw a diagram showing the main functional types of amino acid side chain.

(Note: You do not need to know an specific structures)

A
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23
Q

What charge do the acidic and basic amino acids show an physiological pH?

A
  • Acidic -> Negative because they have already lost their an H -> They contain a carboxyl group and function similar to a carboxylic acid
  • Basic -> Positive because they have already picked up an extra H -> They contain an N and function similar to ammonia
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24
Q

What anagram can be used to remember the amino acid side chain functional types?

A

LHA-AG STAG VITALPTM CSGP

Read as: Laaaaaaaag, stag, vital post-translational modification, computer science GP

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25
Q

What are the charged amino acids?

A

Basic (positively charged):

  • Lysine
  • Histidine
  • Arginine

Acidic (negatively charged):

  • Aspartic acid
  • Glutamic acid
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26
Q

What are the uncharged polar (hydrophilic) amino acids?

A
  • Serine
  • Threonine
  • Asparagine
  • Glutamine
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27
Q

What are the uncharged non-polar (hydrophobic) amino acids?

A
  • Valine
  • Isoleucine
  • Tryptophan
  • Alanine
  • Leucine
  • Phenylalanine
  • Tyrosine
  • Methionine
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28
Q

What are the special cases of amino acid?

A
  • Cysteine
  • Selenocysteine
  • Glycine
  • Proline
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29
Q

What makes glycine unique?

A
  • It contains a hydrogen as its side chain
  • This means that there is much more conformational flexibility in glycine.
  • What this means is that glycine can reside in parts of protein structures that are forbidden to all other amino acids (e.g. tight turns in structures).
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30
Q

What makes proline unique?

A
  • It is the only amino acid where the side chain is connected to the protein backbone twice, forming a five-membered nitrogen-containing ring.
  • So proline is unable to occupy many of the main chain conformations easily adopted by all other amino acids.
  • In this sense, it can be considered to be an opposite of glycine, which can adopt many more main-chain conformations.
  • For this reason, proline can often be found in very tight turns in protein structures (i.e. where the polypeptide chain must change direction).
  • It can also function to introduce kinks into alpha helices, since it is unable to adopt a normal helical conformation -> i.e. It is an alpha helix breaker
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31
Q

Which amino acid is often found in parts of proteins that need to move, such as hinges?

A

Glycine, because it is so small and flexible.

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32
Q

What are the alpha helix breakers and why?

A
  • Proline (Classic helix breaker) -> The side chain interferes strically with the backbone of the chain, forcing a kink in the helix. Also cannot form hydrogen bonds as effectively.
  • Glycine -> Its high conformational flexibility makes it entropically expensive to adopt the relatively constrained α-helical structure.
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33
Q

Describe the concept of amino acid conformers.

A
  • WITHIN the side chain of amino acids that have a C-C bond (i.e. not glycine, alanine and proline), there exist many variations, which exist due to the tetrahedral arrangement of atoms around each carbon.
  • Looking down the axis of the bond, these appear staggered so that the atoms around one carbon appear in the gaps between the atoms around the other carbon.
  • Therefore, the different conformations differ by 120*.
  • Generally, there exists a set of preferred conformations.
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34
Q

What is a post-translational modification?

A

A modification that happens to a protein after translation, usually controlled enzymatically and caused by the synthesis or breaking of covalent bonds.

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35
Q

Give some examples of post-translational modification to amino acids in collagen. How are these clinically relevant?

A
  • Hydroxyproline
    • Permits sharp twisting of the collagen helix and stabilises the triple helix conformation
    • Requires vitamin C to form, so a deficiency results in weaker collagen (scurvey)
  • Hydoxylysine
    • Provides linkage sites for sugars or short polysaccharides, allowing cross-linking of collagen molecules
    • Mutations in the lysine hydroxylase enzyme result in diseases -> e.g. Ehlers-Danlos syndrome (spidery fingers and highly flexible joints)
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36
Q

What are the main post-translational modifications?

A

On syllabus:

  • Disulfide bonding
  • Cross-linking
  • Peptidolysis
  • Glycosylation
  • Phosphorylation
  • Adenylation
  • Farnesylation

Others:

  • Methylation
  • Acetylation
  • Hydroxylation
  • Isoprenylation
  • Ubiquitination
  • Deamidation
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37
Q

Remember to add flashcards on the different PTMs.

A

Do it, using Miffy’s essay.

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38
Q

Around which carbon atom do amino acids show chirality?

A

Alpha-carbon

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39
Q

Which is the only amino acid that does not show chirality?

A

Glycine, since it does not have 4 different atoms around it.

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40
Q

Define chirality.

A

The existence of 4 different atoms around a carbon in an amino acid so that two different configurations are possible that cannot be superimposed.

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41
Q

What are the two configurations for an amino acid called?

A

Enantiomers:

  • D-(Dextro)
  • L-(Laevo)
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42
Q

Which is the only amino acid enantiomer found in living organisms?

A

L, which can be worked out using the CORN law:

  • Look at the amino acid alpha-carbon from the direction of the hydrogen atom
  • In an L-amino acid, the atoms around the carbon should spell out CO-R-N in a clockwise direction
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43
Q

Describe the structural properties of a peptide bond and discuss the significance of this.

A
  • The peptide bond is a single C-N bond in a CO-NH system
  • However, this bond exhibits the resonance hybrid model, where charge is redistributed through the CO-NH system as shown in the diagram
  • This gives the C-N bond the characterstics of a double bond, so that there is no rotation around it
  • Therefore a rigid planar structure arises that limits the number of possible conformations
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44
Q

Draw the resonance hybrid model of a polypeptide.

A
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45
Q

What are the angles in a polypeptide called and why?

A

They are called dihedral angles because the angles around each side of a peptide bond are planar (and a dihedral angle is defined as the angle between two planes).

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46
Q

What are the different angles in a polypeptide and what values do they tend to take on?

A
  • ω (omega)
    • Angle of rotation of the peptide bond (C-N)
    • Is usually 180* (trans) or more rarely 0* (cis)
  • Φ (phi)
    • Angle of rotation of the Cα-N bond
    • Is between -180* and 180*
  • ψ (psi)
    • Angle of rotation of the Cα-C bond
    • Is between -180* and 180*

Note that the phi and psi angles tend to take on values of 60, 180 or -60*.

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47
Q

Label:

A
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48
Q

What values does the omega angle in a polypeptide take on and when is each possible?

A
  • The 180* trans variation is most common, since the cis variation tends to result in too much steric clash
  • Only really proline tends to take on the 0* cis version, since both the cis and trans variations show a similar degree of clash, meaning that both are relatively viable
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49
Q

What is a good way of remembering the psi and phi bonds and their symbols?

A
  • The psi bond has the PSame atoms on each side of the bond, and the symbol is like PSoidon’s trident
  • The phi bond has diPHIrent atoms on each side of the bond, and the symbol looks like a pie being cut in half (pie rhymes with phi)
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50
Q

What is the name for the plot used to show phi and psi angles?

A

Ramachandran plot

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51
Q

What is a Ramachandran plot?

A

A plot showing the different psi and phi angles allowed in a polypeptide chain.

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52
Q

What is on each axis of a Ramachandran plot? How can you remember this?

A
  • Phi on the x-axis and psi on the y-axis
  • You can remember this by thinking that the phi and psi correspond in alphabeticity to x and y
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53
Q

Draw a simple Ramachandran plot.

A
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54
Q

Draw a Ramachandran plot with the following points labelled:

  • Anti-parallel beta sheet
  • Parallel beta sheet
  • Left-handed alpha helix
  • Right-handed alpha helix
  • Collagen helix
A
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55
Q

Define a domain in protein structure.

A

A fundamental unit of tertiary structure, defined as a polypeptide chain, or part thereof, that can fold independently into a stable structure.

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56
Q

Describe how a domain is made up of smaller structures.

A
  • There are 3 main classes of secondary structure elements: alpha helices, beta sheets and turns/loops.
  • Secondary structures can be connected to form simple motifs, which are supersecondary structures (e.g. beta hairpin)
  • These combine to form a domain, which is the fundamental unit of tertiary structure
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57
Q

What are the different forces that hold polypeptides together?

A
  • Covalent bonds (also disulfide bonds)
  • Hydrogen bonds
  • Ionic interactions
  • Van der Waals interactions
  • Hydrophobic effect
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58
Q

What is the most common type of hydrogen bond in proteins and how does the strength vary with distance?

A
  • Between C=O and N-H groups
  • Strength falls off as 1/r6 (i.e. very short range)
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59
Q

Describe how Van der Waals forces occur and draw a graph to show how they vary with separation.

A
  • Exist as attractive or repulsive interactions
  • Attractive forces exist due to fluctuations in the electron densities of neighbouring non-bonded atoms -> Favour tight packing in macromolecules
  • Repulsive forces result from close approaches of electron density clouds
  • The graph shows a decrease of 1/r6
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60
Q

Describe the structure of the alpha helix.

(Angles, residues per turn, hydrogen bonds, directionality, dipole)

A
  • Angles: Around Phi = -60*, Psi = -50* (both negative)
  • Residues per turn = 3.6
  • Hydrogen bonds between the C=O of residue n with the NH residue of n+4 -> So all groups are hydrogen bonded except for the first and last
  • Directionality -> Always right handed (since they are made from L-amino acids)
  • R groups point outwards and do not affect helix
  • Dipole: 0.5 to 0.7 units from C to N terminus
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61
Q

What are some variations of the alpha helix?

A

The standard is the n+4 helix, but rarely there may also be:

  • 310 helix -> n+3
  • π helix -> n+5
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62
Q

Where are alpha helices commonly found?

A

Membrane proteins (e.g. channels, receptors and transporters)

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63
Q

Draw the dipole that exists in alpha helices.

A
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64
Q

Describe the structure of the beta sheet.

(Angles, hydrogen bonds, directionality, dipole)

A
  • Angles: Around Phi = -140*, Psi = 130*
  • Made of strands that are almost completely extended called beta strands
  • These can run either parallel or antiparallel to each other
  • In each strand, the R groups alter between being above and below the strand
  • Regular hydrogen bonds exist between the C=O and N-H of adjacent strands
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65
Q

Draw the structure of a parallel beta sheet.

A
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66
Q

Draw the structure of an antiparallel beta sheet.

A
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67
Q

Where are beta sheets commonly found?

A

Globular proteins

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68
Q

What are loops and turns? What is the difference between them?

A
  • Loops are the structures that connect the alpha and beta structures
  • They are often on the surface, while the alpha helices and beta strands are in the hydrophobic centre
  • Turns are similar to loops, except they contain internal hydrogen bonding between two end residues that makes them tighter and sharper than loops
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69
Q

Describe the structure of loop regions.

A
  • They are often on the surface of proteins
  • Have free C=O and N-H groups to make hydrogen bonds with water molecules
  • Also often have charged and hydrophilic residues
  • The loop is not as sharp as a turn
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70
Q

Where are loop regions commonly found?

A

Usually on the surface of proteins, so they often act as:

  • Binding sites
  • Enzyme active sites
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71
Q

Give a specific example of the role of loop regions in proteins.

A

Antigen binding sites on antibodies are composed of 6 loop regions. These loop regions vary in length and in amino acid sequence between different antibodies.

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72
Q

Are loops and turns always considered to be different?

A

Yes, but sometimes turns are seen as a subset of loops, containing fewer than 5 residues and being much sharper.

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73
Q

What are the regions that connect two antiparallel beta strands called?

A

Hairpin loops, although short hairpin loops are called reverse turns (or just turns).

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74
Q

What are the types of turn and how do they differ? Draw diagrams.

A

Type I and Type II -> They differ by the positional restraints on the amino acid R2.

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75
Q

What is a synonym for a simple motif?

A

Supersecondary structure

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76
Q

Give some examples of common simple motifs.

A
  • Helix-turn-helix motif -> Found in DNA binding proteins and calcium binding proteins
  • Hairpin beta motif -> Two adjacent antiparallel beta strands joined by a loop
  • Greek key motif -> 4 adjacent antiparallel beta strands
  • Beta-alpha-beta motif -> A common way to connect beta strands
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77
Q

Explain the concept of structural homology.

A

If there are large similarities between the amino acids in two domains, then the domains will have similar structures.

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78
Q

Do motifs always need the same amino acid sequences to form?

A

No, so the similar domain structures frequently occur in different proteins with different functions and with different amino acid sequences.

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79
Q

What are the two states of a protein?

A
  • Native -> When a protein is properly folded and/or in the assembled form, which is operative and functional.
  • Denatured -> When a protein loses the secondary, tertiary and quaternary structure that gives it its functionality.
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80
Q

Is the native state always the most stable conformation for a protein?

A

No, at various temperatures and pressures the native state may not be the most stable.

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81
Q

What is the most important driving force in protein folding and why?

A
  • Hydrophobic effect
  • Because the universe tends towards disorder (second law of thermodynamics) and non-polar segments of the protein restricts the conformational freedom of the surrounding water molecules
  • Therefore, folding the non-polar regions away from the water is more thermodynamically favourable
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82
Q

Describe the counter-acting forces of proteins at equilibrium.

A

The attractive forces in the folded state overcome the unfavourable restrictions on the conformational freedom of the polypeptide chain.

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83
Q

Describe what disulfide bridges are and where they may be found.

A
  • Covalent bonds between two cysteine residues (S-S)
  • These may be within a single polypeptide or between polypeptide chains (like in insulin)
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84
Q

What are the different types of electrostatic interaction and how does the strength of each change with distance?

A
  • Charge-charge
  • Charge-dipole
  • Dipole-dipole

E = q1q2/εRn

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85
Q

What is the importance of the change in energy of an electrostatic interaction?

A

The rate at which some of the stronger electrostatic interactions decrease with distance is relatively slow, meaning that they may act over long distances and contribute to tertiary and quarternary structures.

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86
Q

What is the strength of electrostatic interactions in the centre of a protein like?

A

These interactions tend to be stronger because the interior of the protein is hydrophobic and so the dielectric constant is lower.

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87
Q

What are the different types of multi-subunit proteins?

A
  • Homo-oligomeric -> All of the subunits are identical (e.g. dimer, trimer)
  • Hetero-oligomeric -> Made of more than one type of sub-unit
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88
Q

What is the Levinthal paradox?

A
  • Proteins cannot randomly sample the theoretical number of possible conformational states that would enable them to find the correct, native fold.
  • If each residue had two states, either 𝛼 or 𝛽, a 100 residue peptide would have 2100 or 1030 possible conformations. If the rate of conversion was ~ 10-13 seconds, then it would take ~ 1010 years…
  • Therefore it was decided that proteins must have evolved mechanisms of efficient, guided folding pathways.
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89
Q

Describe the thermodynamics of protein folding and what determines whether a protein’s native state is stable.

A
  • The Denatured to Native transition can be notated as:
    • ∆GD → N = G (N) – G (D)
  • If ∆GD → N is negative then the reaction is spontaneous and therefore the protein is stable.
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90
Q

How can the stability of a protein be affected by mutations?

A
  • Mutations may increase the Gibbs free energy of the native state, so that the energy difference between the native and denatured state is reduced.
  • This reduces the stability of the protein and shifts the equilibrium towards the denatured state.
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91
Q

Give an alternative way of considering the denatured to native state protein transition.

A
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92
Q

How can protein folding be observed?

A

Removing the denaturant from the protein, so that it can fold.

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93
Q

Describe the 3 stages of protein folding that are observed.

A
  1. Fast collapse and secondary structure formation. Formation of what is commonly called the ‘molton globule’ state. Characterised by a reduction in the radius of gyration to 10% larger than the native state.
  2. Appearance of tertiary structure (ms to seconds). Interactions between nascent secondary structure elements build up, mutually stablising their states through interactions. Side chain conformations are still mobile, although the core of the protein starts to fix.
  3. Final formation of the native state, typically less than a second. Resulting in the locking together of buried side chains to form highly ordered compact networks of interactions.
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94
Q

What are molecular chaperones and how do they work?

A
  • Enzymes that assist with the folding of a protein
  • They work by unfolding misfolded proteins and allowing the protein to try again at folding
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95
Q

What is a co-factor?

A
  • A non-protein chemical compound or metallic ion that is required for an enzyme’s activity as a catalyst, a substance that increases the rate of a chemical reaction.
  • It can either be a metallic ion or organic molecules (called coenzymes)
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96
Q

Give an example of a process that uses many co-factors.

A

Electron transfer

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97
Q

Describe the main tertiary domain types.

A
  • Alpha structures
  • Beta structures
  • Alpha-beta structures -> Including alpha/beta and alpha+beta structures
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98
Q

What are alpha domains?

A

Proteins whose core structures have mostly alpha helices in their secondary structure.

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99
Q

What are beta domains?

A

Proteins whose core structures have antiparallel beta sheets in their secondary structure. This usually involves two sheets with strands of various lengths and numbers.

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100
Q

What are alpha-beta domains?

A

Proteins with a mixture of alpha and beta secondary structures. The most common type are alpha/beta, which consist of a central beta sheet surrounded by alpha helices.

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101
Q

For each domain type, list the different protein types it can be found in.

A

Alpha domain:

  • Membrane proteins (e.g. channels, receptors, transporters)
  • DNA & RNA binding proteins (e.g. transcription factors)
  • Connective tissues (e.g. collagen)
  • Coagulating proteins (e.g. fibrinogen)

Beta domain:

  • Enzymes
  • Transport proteins
  • Antibodies
  • Cell surface proteins
  • Virus coat proteins

Alpha-beta domain:

  • Enzymes
  • Proteins that bind and transport metabolites
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102
Q

Consider adding more flashcards on the different tertiary domain types.

A

Do it!

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103
Q

Give an example of a protein where mutliple domains are combined to give the functional protein.

A

Ligand-gated ion channels

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104
Q

Give an essay plan outlining the different post-translational modifications. (Make full notes on this later!)

A

Phosphorylation

  • add phosphate groups onto aa’, negatively charged so can attract positive side chains via ionic interactions
  • particularly important in intracellular signalling protein kinases
  • eg MLCK phosphorylation inactives MLCK in intracellular signalling for smooth muscle relaxation
  • increasing inotropy in the heart
  • regulation of translation : insulin can trigger an intracellular cascade leading to the phosphorylation of 4E binding proteins, which would usually prevent the 5’ methylated guanosine cap from forming, preventing ribosome from being recruited, but phosphorylation prevents this action to increase and regulate translation

Hydroxylation

  • hydroxylase enzymes adds -OH groups onto collagen, fibrous protein with sequence of Gly-X-Y, glycine-hydroxylysine-hydroxyproline
  • lysyl and prolyl hydroxylases will add -OH groups to proline and lysine residues, meaning water can form OH bonds with them, underlying collagens tensile strength due to cross links between triple helix, water providing incompressibility

Ubiquitination

  • misfolded proteins tagged to be broken down by ubiquitin ligases, and directed to proteasomes
  • prevents protein from carrying out disruptive function or aggregating

Glycosylation

  • process of adding oligosaccharides to proteins to make glycoprotein
  • lectins are proteins that glycans add to specifically
  • usually added to -OH groups on serine, threonine, tyrosine, via O-linked glycosylation taking place extracelluarly or N-linked glycosylation occurring where glycan added to N atom on an aa’
  • glycoproteins produced from this reaction are important for cell signalling, interaction and adhesion
  • eg fibronectin and laminin glycoproteins in basement membrane which bind integrins, and blood group tags

Adenylation

  • uses cAMP as a substrate, addition of AMP to proteins
  • important in cell signalling

Farnesylation, addition of c15 goup, also important in cell signalling

-Important in order to activate amino acids for example aminoacyl tRNAs are found through activating the amino acid thorugh adding AMP and this facilitates the addition of tRNAs.

Acetylation

  • addition of acetyl-coA groups to proteins, by acetyltransferases eg histone acetyl transferase
  • histone proteins H2A H2B H3 H4
  • masks positive charge of lysine, so histone group less attracted to DNA
  • can be used to control gene expression, important in differentiation when cell type specific gene expression is required to retain cells in their terminally differentiated state

Allosteric regulation

Important for proteins in order to activate and inactive enzymes but also important in molecules such as DNA as they show cooperativity due to allosteric binding.

Cleavage

Can be used in order to active pro hormones to hormones that would otherwise be damaging to a cell.

Additional

Addition of cofactors

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105
Q

Give two examples of co-operativity or allostery in proteins.

A
  • Haemoglobin -> One oxygen binding makes it easier for another to bind. This results in a sigmoidal dissociation curve.
  • Phosphofructokinase -> One of the most important regulatory enzymes of glycolysis. Allosteric inhibition can be used to regulate the rate of respiration in response to chemical levels (e.g. levels of ATP).
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106
Q

What are the two functional types of fibrous proteins?

A
  • Active proteins
  • Passive structural proteins
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107
Q

Describe the amino acid sequence in fibrous proteins.

A

It is often a repeating sequence of amino acids, although this repetition does not need to be perfectly consistent.

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108
Q

Describe the structural types of fibrous proteins.

A
  • Coiled coil alpha helices -> Keratin, Myosin
  • Collagen triple helix
  • Beta sheets in amyloid fibres and silks
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109
Q

Describe the structure of collagen.

A
  • Made up of 3 left-handed polypeptide strands that are coiled into a right-handed collagen helix
  • Each strand contains lots of glycine because it is the only amino acid small enough to fit into the crowded interior of the triple helix
  • General structure: -Gly-X-Y-Gly-X-Y-
    • X: typically proline
    • Y: typically hydroxyproline
  • Collagen molecules are assembled parallel to each other but are staggered, forming a long fibril -> These fibrils are stabilised by cross-linkages, largely between the hydroxylated amino acids, like hydroxylysine
  • Fibril assembles into a collagen fibre
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110
Q

What type of protein does collagen exemplify?

A

Fibrous

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111
Q

What are the causes and symptoms of Ehlers-Danlos syndrome?

A
  • Causes: Different types, all caused by defects in collagen, usually genetic
  • Symptoms: Stretchy skin, Joint hyperflexibility, Weak and easily bruised skin
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112
Q

What is the name for the immature and mature form of collagen?

A
  • Immature = Procollagen
  • Mature = Tropocollagen
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113
Q

Describe the process of maturation of collagen.

A
  • Collagen molecules are laid down by fibroblasts as procollagen
  • Peptidases cleave the amino and carboxy termini allowing the formation of the mature form, tropocollagen.
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114
Q

Give an example of a globular protein.

A

Histones

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115
Q

Describe the structure of histones.

A
  • They are globular proteins
  • 8 histone proteins form an octamer -> When DNA wraps around this, the whole unit is called a nucleosome
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116
Q

What is the need for histones?

A

They save space in the nucleus by packing the DNA very tightly.

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117
Q

Define catalysis.

A

The increase in rate of a chemical reaction by a catalyst, which is unchanged at the beginning and end of the reaction.

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118
Q

Define enzyme.

A

A catalyst that is produced by a biological organism.

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119
Q

Describe whether an enzyme is changed by the reaction it catalyses.

A

The enzyme is not changed at the beginning and end of a reaction, but it can be changed during the reaction.

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120
Q

What are the units for Gibbs free energy?

A

kJ mol-1

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121
Q

Describe how an enzyme affects the energy and rates in a reaction.

A
  • An enzyme speeds up a reaction by providing a pathway that has a lower energy path
  • Larger k1 and k-1
  • Lower ΔG1 and ΔG-1 (energy changes of the formation of the transition state and formation of the product respectively)
  • But ΔG0 (energy change of reaction) remains the same
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122
Q

Explain why there are dips in the graph for the catalysed reaction.

A

When an enzyme-substrate complex is formed, there is a drop in energy.

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123
Q

Explain what transition states and reaction intermediates are.

A
  • Transition states are the states in which the reactants exist just before the product is formed (i.e. when all the bonds have been broken). They are the highest points on an energy-time graph.
  • Intermediates are entities that are formed as a result of the substrates reacting, and which will react again to form the final product. They are indicated by any dips in the graph.
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124
Q

Name some classes of biochemical reaction you need to know.

A
  • Hydrolysis
  • Ligation
  • Condensation
  • Group-transfer
  • Redox
  • Isomerisation
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125
Q

What are hydrolysis reactions?

A

Organic chemical reactions that involve adding water to break apart molecules.

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126
Q

What are ligation reactions?

A
  • Reactions where two DNA fragments are joined by a phosphodiester bond
  • This is catalysed by a ligase enzyme
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127
Q

What are condensation reactions?

A

A reaction where two molecules are joined and a small molecule is released. It is often water.

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128
Q

What is the difference between a condensation and a dehydration reaction?

A
  • Condensation -> When a small molecule is released
  • Dehydration -> When thesmall molecule released is specifically water
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129
Q

What are group-transfer reactions?

A

A reaction where one or more groups of atoms is transferred from one molecule to another.

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130
Q

What are redox reactions?

A

A type of chemical reaction that involves a transfer of electrons between two species. One species is oxidised while another is reduced.

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131
Q

What are isomerisation reactions?

A

When one molecule is transformed into another molecule which has exactly the same atoms, but the atoms have a different arrangement e.g. A-B-C → B-A-C

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132
Q

What is the importance of the active site in terms of action of enzymes?

A
  • It is the site of catalysis
  • It allows for specificity
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133
Q

What are multimeric enzymes?

A

Enzymes that contain more than one polypeptide chain.

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134
Q

What are isozymes and why are they important?

A
  • Enzymes that have a different amino acid sequence and are encoded by different genes, but catalyse the same reaction
  • They usually have different kinetic parameters, such as a different Km, so that they can be used to mediate a process to the level at which it is required for that tissue at that stage of development
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135
Q

Give an example of an isozyme.

A
  • LDH (lactate dehydrogenase) is an enzyme used in converting lactate to pyruvate and back
  • There are 5 different isozymes for LDH -> There are 4 subunits in LDH and each one can be one of two different types
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136
Q

What are multienzyme complexes?

A
  • Stable assemblies of more than one enzyme, generally involved in sequential catalytic transformations.
  • Note that they are different from multienzyme polypeptides, where multiple active sites are within one polypeptide chain.
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137
Q

Give an example of a multienzyme complex.

A

Pyruvate dehydrogenase complex -> A complex of three enzymes that converts pyruvate into acetyl-CoA by a process called pyruvate decarboxylation. The acetyl-CoA may then be used in the Krebs cycle, so this multienzyme complex is important in linking glycolysis to the Krebs cycle.

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138
Q

Describe an enzyme activated by subunit dissociation.

A
  • cAMP-dependent protein kinases
  • These are made out of a regulatory and catalytic subunit
  • When cAMP binds to the regulatory subunit, the catalytic subunit dissociates and becomes uninhibited, so that it can perform its normal function
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139
Q

What are the two types of co-factor?

A
  • Co-enzymes -> Organic
  • Inorganic ions
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140
Q

What are co-enzymes derived from?

A

Vitamins

(Check if you need to know specific vitamins and exampels)

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141
Q

What two concentrations does the rate of an enzyme catalysed reaction depend on?

A
  • Enzyme concentration
  • Substrate concentration
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142
Q

Describe the equation that can be used to model an enzyme-catalysed reaction.

A
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143
Q

What is Michaelis-Menten behaviour?

A

Michaelis-Menten behaviour is a kinetic model commonly exhibited by enzymes that catalyse a single-substrate equation and which do not feature co-operativity, resulting in a rate-substrate concentration graph of a rectangular hyperbolic shape

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144
Q

What are some important variables in Michaelis-Menten kinetics?

A
  • Km (Michaelis constant)
  • Vmax (Maximal velocity)
  • Kcat (Turnover number)
  • Kcat/Km (Specificity constant)
145
Q

What shape graph is characteristic of Michaelis Menten kinetics?

A

Rectangular hyperbola

146
Q

What is Km, what does it indicate and what are the units?

A
  • Michaelis constant
  • It is the substrate concentration that produces half the maximal reaction rate (Vmax) -> Therefore it is a measure of affinity
  • It is a property of each enzyme molecule
  • Units: M (or mol/dm3)
147
Q

What does a low Km value indicate?

A

A high affinity.

148
Q

What is Vmax, what does it indicate and what are the units?

A
  • Maximal velocity
  • The maximal rate of reaction possible with a given enzyme amount
  • Units: mol/sec (Check this!)
149
Q

What is Kcat, what does it indicate and what are the units?

A
  • Turnover number
  • The number of substrate molecules each enzyme site converts to product per unit time
  • Units: s-1

Note: Kcat = k2

150
Q

What is Kcat/Km, what does it indicate and what are the units?

A
  • Specificity constant
  • It is a measure of how efficiently an enzyme converts substrates into products
  • Unit: M-1s-1
151
Q

Do Vmax, Km and Kcat vary with enzyme concentration?

A

Vmax does, but Km and Kcat do not, since they are properties of each enzyme molecule.

152
Q

In terms of reaction variables, how can Vmax be increased?

A

By increasing Kcat.

153
Q

What is Ki?

A

The concentration of inhibitor at which the reaction rate is half of Vmax (assuming that the substrate is saturating).

154
Q

What is the Michaelis-Menten equation?

A

v = Vmax[S] / (Km + [S])

155
Q

Draw the graph showing Michaelis-Menten behaviour, with all of the variables labelled.

A
156
Q

What two assumptions can be made in order to derive the Michaelis-Menten?

A
  • Equilibrium assumption
    • Makes use of the idea that k1 and k-1 sometimes differ to a negligible extent, so that E + S <-> ES is an equilibrium that is not greatly affected by the ES -> E + P reaction
    • However, this assumption only weakly applies in situations where [S] is very low (so that k1 is too low) or where k2 is large enough for ES to be near instantly converted to the product
  • Steady state assumption
    • Assumes that ES is in steady state and so [ES] does not change as the reaction progresses.

Both assumptions lead to a derivation that results in the equation V = (Vmax[S]) / (Km + [S]), where V is the initial reaction rate at a given [S]

157
Q

How can a normal velocity-substrate conentration curve be changed to enable identification of kinetic parameters?

A
  • A Lineweaver Burk plot (a.k.a. double reciprocal plot) can be plotted
  • This is a plot of 1/v against 1/[S]
158
Q

What does a Lineweaver Burk (double reciprocal plot) allow to be determined?

A
  • y-intercept = 1/Vmax
  • x-intercept = -1/Km
  • Gradient = Km/Vmax
159
Q

Describe competitive inhibition. What is the effect on the rate-substrate concentration graph?

A
  • An inhibitor can compete for the same binding site at the substrate – often the active site
  • But this means that inhibition can be overcome by increased substrate concentration
  • Km is increased, but Vmax stays the same
160
Q

Describe non-competitive inhibition. What is the effect on the rate-substrate concentration graph?

A
  • Allosteric interaction represent ‘long distance’ interactions between binding sites on the protein.
  • These sites, located in distinct domains of the protein, interact via conformational changes.
  • Unaffected by changes in substrate concentration
  • Vmax is reduced, but Km is unchanged
161
Q

What is irreversible inhibition?

A
  • Reversible inhibitors usually covalently modify an enzyme, and inhibition can therefore not be reversed.
  • Irreversible inhibitors often contain reactive functional groups that react with amino acid side chains to form covalent adducts.
162
Q

Describe how competitive inhibition appears on a double reciprocal graph (Lineweaver Burk)?

A
163
Q

Describe how non-competitive inhibition appears on a double reciprocal graph (Lineweaver Burk)?

A
164
Q

What are the two models of enzyme catalysis and how do they differ?

A
  • Induced fit model -> Substrate induces the conformational change
  • Selected fit model -> Selects and stabilizes a complementary conformation from a pre-existing equilibrium of ground and excited states of the protein
165
Q

What are the two points at which an enzyme’s functioning can be inhibited?

A
  • Inhibiting or promoting substrate binding (affect KM)
  • Inhibiting or promoting formation/release of products (affect Kcat)
166
Q

What is allosteric control?

A

The regulation of an enzyme by binding an effector molecule at a site other than the enzyme’s active site.

167
Q

What is the difference between allosteric control and non-competitive inhibition?

A

Non-competitive inhibition is a type of allosteric control.

168
Q

What is co-operativity?

A

The process when the binding of one ligand to a protein causes the affinity for the binding of another molecule of the same ligand to either increase or decrease.

169
Q

What are the different types of co-operativity?

A
  • Positive -> Binding of one ligand increases the affinity for the second
  • Negative -> Binding of one ligand decreases the affinity for the second
170
Q

What is the shape of the rate-substrate concentration graph for positive co-operativity?

A

Sigmoidal

171
Q

What is the shape of the rate-substrate concentration graph for negative co-operativity?

A

Hyperbolic like that of an enzyme without co-operativity, except Vmax is typically lower and is reached at a lower substrate concentration (lower Km).

172
Q

What are allosteric enzymes?

A

Allosteric enzymes are enzymes that undergo a conformational change upon the binding of a ligand (known as the effector) at a site other than the active site, which changes the enzyme’s catalytic rate. The effector may be an activator if it increases the enzyme’s normal activity or an inhibitor if it decreases it.

173
Q

What are the two types of allosteric control?

A
  • Homotropic regulation -> Where the effector is the same molecule as the substrate.
  • Heterotropic regulation -> Where the effector is a different molecule to the substrate.
174
Q

Describe why allosteric enzymes do not follow Michaelis-Menten kinetics.

A
  • Allosteric enzymes have multiple active sites
  • These sites exhibit cooperativity
  • Therefore this results in a sigmoidal curve (or hyperbolic if negative cooperativity)
175
Q

Describe the structure of allosteric enzymes.

A
  • Most allosteric proteins are made up of many similar subunits (known as oligomers).
  • As oppose to this, monomeric enzymes are usually Michaelis-Menten-abiding enzymes.
  • This said, there is increasing evidence that not all allosteric enzymes are oligomeric, or even composed of multiple subunits, which means that a small number of allosteric proteins are monomeric. It has been postulated that this is as a result of evolution driving the “stitching” of separate genes into a single gene that encodes a protein responsible for multiple functions. Such an enzyme would contain more than one binding site per subunit, an example being the enzyme glutamate dehydrogenase. However, there also exist examples of allosteric proteins that are monomeric and contain only a single ligand binding site, such as glucokinase, which has a single binding site for glucose and yet displays a sigmoidal curve that is indicative of positive co-operativity. Currently, the mechanism explaining this phenomenon is not fully clear.
176
Q

Describe the effect of allosteric ligands on rate-substrate concentration graph.

A
  • Positive effectors give rise to activation
    • Decreasing the KM, increasing the Vmax
    • Therefore curve shifts left and/or up
  • Negative effectors give rise to inhibition
    • Increasing the KM, or decreasing the Vmax
    • Therefore curve shifts right and/or up
177
Q

Can cooperativity be homotropic and heterotropic?

A

Yes, but we usually consider positive homotropic cooperativity in sigmoidal curves.

178
Q

Give an example of a enzyme that demonstrates the importance of cooperativity and allostery.

A
  • Phosphofructokinase (PKF) shows a strong positive co-operativity (and can be regulated by other allosteric inhibitors and activators)
  • It is used to catalyse the ATP-dependent conversion of fructose 6-phosphate to fructose 1,6-bisphosphate (and ADP), which is a step that commits to the process of glycolysis, so the control of the rate of respiration is highly dependent on PKF activity.
  • At low-to-medium substrate concentrations, the rate of glycolysis is low, but at medium-to-high substrate concentrations, the rate of glycolysis is high.
  • The importance of this is that glycolysis becomes an almost binary process (either very fast or very slow), with only a narrow range of substrate concentrations that lead to average reaction rates, so that the system can very quickly revert to a set substrate concentration when deviation occurs.
179
Q

Suggest why negative cooperativity may be important.

A

It has been proposed that the importance of negative co-operativity pertains to the increased range of substrate concentrations at which the enzyme can convert the substrate, which comes at the cost of a weaker response. This is exemplified by some G-protein coupled receptors that exhibit negative co-operativity.

180
Q

What are the two main models of cooperativity?

A
  • Concerted (MWC)
  • Sequential (KNF)
181
Q

Describe the concerted (MWC) model of cooperativity.

A
  • All of the subunits of the protein show functional symmetry, and each can take on either the R (relaxed) or T (tense) conformational states.
  • The T state is the inactive form, while the R state is the active form.
  • The R and T states are in an equilibrium at all times, and since all of the subunits are functionally symmetrical, all of the subunits shift simultaneously between T and R states.
  • Co-operativity is explained by the idea that the binding of a substrate molecule shifts the equilibrium, so that in positive co-operativity binding results in a higher probability of the enzyme existing in the relaxed active form.
  • Additionally, heterotropic inhibitors induce the T form, while activators induce the R form.
182
Q

Describe the sequential (KNF) model of cooperativity.

A
  • All of the protein subunits each can take on either the R (relaxed) or T (tense) conformational states
  • The T state is the inactive form, while the R state is the active form.
  • Subunits do not need to maintain functional symmetry.
  • The binding of a ligand to a subunit only directly causes that one subunit to change between the R and T states, but the co-operative effect occurs because this binding increases (or decreases in negative co-operativity) the affinity at other sites, until all of the sites are occupied.
183
Q

Compare simply how the two models of cooperativity work.

A
  • The concerted model states that binding of the substrate causes the affinity of the protein to change due to a change in the quaternary structure of the protein
  • The sequential model implies it is due to tertiary level changes (which also affect the quaternary structure).
184
Q

Which out of the relaxed and tense states is active in cooperativity?

A

Relaxed

185
Q

What is the importance of positive cooperativity?

A

It increases sensitivity to the substrate over a short substrate concentration window.

186
Q

Compare haemoglobin and myoglobin in terms of where they are found and their cooperativity.

A
  • Haemoglobin
    • Supplies oxygen all over the body
    • Has multiple subunits and therefore shows cooperativity
    • Lower affinity for oxygen
  • Myoglobin
    • Supplies muscle with oxygen
    • Has only one subunit and therefore no cooperativity
    • Higher affinity for oxygen
187
Q

What is ATCase?

A
  • Aspartate transcarbamylase
  • It catalyses the first step of the pyrimidine synthesis pathway, forming N-carbamoyl aspartate from carbamoyl phosphate and aspartate
188
Q

Describe allostery in ATCase.

A
  • Aspartate transcarbamylase is involved in the first step of the pyrimidine synthesis pathway, forming N-carbamoyl aspartate from carbamoyl phosphate and aspartate.
  • The composition of the subunits is C6R6, forming 2 trimers of catalytic subunits and 3 dimers of regulatory subunits.
  • ATCase can be inhibited by CTP, the end product of the whole pathway (binds to REGULATORY subunits)
  • ATCase can be activated by the substrate (binds to CATALYTIC subunits)
189
Q

What is the importance of drugs as allosteric ligands?

A

Drugs that are allosteric ligands are useful for the selective regulation of enzymes/receptors that have similar active or receptor sites to each other.

190
Q

What are the main mechanisms of enzyme regulation?

A
  • Covalent (via chemical modification)
    • Proteolysis
    • Phosphorylation
  • Non-covalent (via allosteric control)
191
Q

Draw a table showing all of the ways of controlling enzyme action.

A
192
Q

Describe how proteolysis can be used to regulate enzyme activity.

A
  • Many proteins are synthesised in a ‘pro’ or inactive form (zymogen)
  • Usually the ’pro-protein’ form contains an additional sequence of amino acids
  • The active or functional form of the protein is only liberated following proteolytic cleavage of the additional sequence -> Ensures that it is activated at the right time and in the right place
193
Q

Describe how digestive enzymes are activated.

A
  • Proteolytic enzymes such as trypsin and chymotrypsin (small intestine) and pepsin (stomach) are synthesised as zymogens.
  • Proteolysis of these in their respective areas of action is used to expose the active site.
194
Q

Describe how covalent modification is involved in the blood clotting mechanism.

A
  • Blood clotting involves two main pathways, called the intrinsic (damaged surface) and extrinsic (trauma) pathways, which converge into a final common pathway
  • They converge in the activation of factor X, which is an endopeptidase used to cleave prothrombin into thrombin in to places
  • Thrombin then cleaves fibrinogen (secreted by fibroblast cells) into fibrin
  • Fibrin has two domains, D and E, which aggregate into proteofibrils.
  • FIbrin also activates factor XIII, which cross links the fibrin protein together, forming a stable mesh
195
Q

Describe which proteins can be phosphorylated and how they can be phosphorylated and dephosphorylated.

A
  • Phosphorylation tends to occur on OH groups, which are found on serine, threonine and tyrosine
  • Phosphorylated by protein kinases using phosphates from ATP (or AMP)
  • Dephosphorylated by phosphatases
196
Q

Why is phosphorylation so common?

A
  • Serine, tyrosine and threonine are uncharged
  • Transfer of phosphate from ATP to an OH group is very energetically favourable (i.e. all target converted)
  • Phosphorylation of these residues introduces a bulky and negatively charged moiety
  • Phosphorylation will introduce large conformational changes due to electrostatic repulsion/attraction
  • These conformational changes can alter substrate binding or intra-protein communication
197
Q

What is a phosphorylation cascade?

A
  • A sequence of events where one enzyme phosphorylates another, causing a chain reaction leading to the phosphorylation of thousands of proteins
  • It can be seen with the singal transduction of hormone messages
198
Q

What is the importance of phosphorylation cascades?

A

They can be used to rapidly amplify a signal transmitted to a cell inside the cell.

Examples of signal transduction:

  • Cell cycle
  • Glycogen breakdown
  • Transcriptional regulation
  • Cell growth and development
199
Q

What is mevanolin?

A
  • It is a HMG-CoA reductase inhibitor (a.k.a. a statin)
  • It is used to lower blood cholesterol
200
Q

What makes lipids insoluble in water?

A

Large regions of the surface composed of hydrocarbons with very few polar groups.

201
Q

Give some of the roles of lipids.

A
  • Energy storage
  • Membranes
  • Insulation
  • Chaperones for protein folding
  • Light absorber (chlorophyll, retinal)
  • Energy transduction (retinyl component attached to rhodopsin)
  • Electron transfer (coenzyme Q)
  • Hormone (testosterone, progesterone)
  • Vitamins (vitamin A, E, D and K)
  • Antioxidants (vitamin E)
  • Signaling molecules (ceramides)
202
Q

What are the two major divisions of lipids?

A
  • Simple -> Esters of fatty acids and glycerols or alcohols
  • Complex -> Contain other groups, such as phosphate groups
203
Q

What are the 8 types of lipid?

A
  • Fatty acid
  • Glycerolipid (including triglycerides)
  • Glycerophospholipid (a type of phospholipid)
  • Sphingolipid (a type of phospholipid)
  • Sterol lipid
  • Prenol lipid
  • Saccharolipid
  • Polyketide
204
Q

What is a fatty acid?

A
  • A monocarboxylic acid, usually with a long unbranched aliphatic tail that may either by saturated or unsaturated
  • It is the fundamental building block of lipids
205
Q

Describe the general structure of fatty acids.

A
  • Hydrophilic carboxyl head
  • Saturated or unsaturated hydrophobic tail
206
Q

What are the different types of fatty acid depending on their length?

A
  • Short-chain fatty acids (5 or fewer carbons)
  • Medium-chain fatty acids (6 to 12 carbons)
  • Long-chain fatty acids (13 to 21 carbons)
  • Very long-chain fatty acids (22 or more carbons)
207
Q

What is the difference between fats and lipids?

A

Lipids are the general group of molecules that are soluble in non-polar solvents. Fats are a subdivision of lipids and are esentially triglycerides (double-check this!).

208
Q

Describe the naming of the carbons on a fatty acid molecule.

A
209
Q

What is the maximal number of double bonds a fatty acid chain can have?

A

6

210
Q

Describe fatty acid nomenclature.

A

e.g. 18:2 ∆9, 12 or 18:2 (ω-6) or 18:2 (n-6)

  • The first number (18) indicates the number of carbons
  • The second number (2) indicates the number of double bonds
  • 18:2 ∆9, 12 ->The delta numbers indicate the position of the double bonds, with the first double bond being counted from the alpha (carboxyl) end
    • It is assumed that the bonds as cis, unless a ‘t’ is put after a number
  • 18:2 (ω-6) or 18:2 (n-6) -> The omega or n numbers indicate the number of the double bond closest to the omega (non-carboxyl) end
211
Q

Give the omega name for this fatty acid.

A

C20:5 (ω-3)

212
Q

What are essential fatty acids?

A

Fatty acids that are necessary for human health but which cannot be synthesised by the body and must therefore be ingested.

213
Q

What are two essential fatty acids?

A
  • Alpha-linolenic acid (an omega-3 fatty acid)
  • Linoleic acid (an omega-6 fatty acid)
214
Q

What is the importance of trans fatty acids?

A
  • TFAs enter the diet through dairy products, meat and partially hydrogenated plant oils that are commonly found in processed food.
  • TFAs are suspected of disrupting the membrane bilayer, thus its function, and are linked to heart disease.
215
Q

What are isoprenoid fatty acids and what is their importance?

A
  • Branched fatty acids containing repeating methyl branches called isoprenoids.
  • Appear to be made of long polymers of a 5-carbon branched compound called Isoprene.
  • Their role is to disrupt lipid packing and anchoring important biochemicals to the membrane (Vitamin A and Coenzyme Q).
216
Q

How many carbons do fatty acids in humans tend to contain?

A

An even number.

217
Q

What is the function of double bonds in fatty acids?

A

Induces a kink, which disrupts tight lipid packing in membranes, thus increasing the packing free volume ‘breathing space’ for normal membrane protein function (channels, receptors and transporters to function).

218
Q

What are the sources of fatty acids?

A
  • Dietary
  • De Novo synthesis
219
Q

Describe how diglycerides and triglycerides are synthesised.

A
  • Carboxyl groups of fatty acids are made more reactive by the addition of coenzyme A, which contains a highly reactive thiol group
  • These are they used along with glycerol to make diglycerides and triglycerides
220
Q

Describe the function of diglycerides.

A
  • Signalling molecules
  • Synthesis of triglycerides
221
Q

Describe the function of triglycerides.

A
  • Storage
  • Transport
222
Q

Describe the structure of diglycerides and triglycerides.

A

2 or 3 fatty acid molecules joined by ester bonds to a glycerol molecule.

223
Q

How are fatty acids joined to the rest of the molecule in lipids?

A
  • Oxygen ester bond (e.g. in triglycerides)
  • Amide bond (e.g. in sphingolipids) (Note: This can be thought of as a ‘nitrogen ester’)
  • Thioesters
224
Q

How can ester bonds in a lipid be hydrolysed?

A

Boiling in NaOH or KOH.

225
Q

What is the more correct term for phospholipids?

A

Glycerophospholipids

226
Q

Describe the structure of a phospholipid.

A
  • One glycerol
  • Two fatty acids
  • One phosphate
  • One alcohol -> This is attached to the phosphate and varies between phospholipids
227
Q

What phospholipid classes do you need to know about and what is the alcohol group of each?

A
  • PA -> Phosphatidic acid -> No alcohol
  • PE -> Phosphatidylethanolamine -> Ethanolamine
  • PC -> Phosphatidylcholine -> Choline
  • PS -> Phosphatidylserine -> Serine
  • PI -> Phosphatidylinositol
  • CL -> Cardiolipin (a.k.a. diphosphatidylglycerol) -> Phosphatidylglycerol
228
Q

Name the different head groups in phospholipids and their charges.

A
229
Q

What is the role of phosphatidic acid in the cell?

A
  • Smallest phospholipid
  • Gives curvature to membranes
  • Ca2+ can be used to aggregate several PAs and create a patch sensitive to temperature and pH
230
Q

What is the role of phosphatidylethanolamine in the cell?

A
  • Found in cell membranes -> Particularly prevalent in nerve tissue
  • Contains primary amine and therefore has a highly reactive chemical handle that can be easily modified
231
Q

What is the role of phosphatidylcholine in the cell?

A
  • Major structural protein in membranes
  • This is because it allows tight packing, partly due to the zwitterionic nature that means no charge disruption
232
Q

What is the role of phosphatidylserine in the cell?

A
  • Enriched in brain tissue -> Suggests an important role in cognition -> Also declines with age
  • Involved in many functions, including anchoring proteins in the membrane
233
Q

What is the role of phosphatidylinositol in the cell?

A
  • Plays only a minor role in the membrane
  • Mostly involved in signalling -> Particularly abundant in the brain
  • Can be phosphorylated in 3 places, producing phosphatidylinositol phosphates
    • e.g. PIP2 can be converted into DAG and IP3 by phospholipase C
234
Q

What is the role of cardiolipin in the cell?

A
  • Found predominantly in the mitochondrial inner membrane
  • Stabilises proteins in the electron transport chain
235
Q

Describe infant respiratory distress syndrome.

A
  • Pulmonary surfactant is a mixture of phospholipids and lipoproteins secreted by type II pneumocytes.
  • It diminishes the surface tension of the water film that lines alveoli, thereby decreasing the tendency of alveoli to collapse and the work required to inflate them.
  • If there are problems with these molecules, then the lungs have trouble inflating and the infant may need to be placed on a ventilator.
236
Q

What enzymes are used to degrade phospholipids?

A
  • Phospholipases A1 and A2 are used to remove the acyl chains
  • Phospholipase C is used to remove the head group
237
Q

Describe the structure of sphingolipids.

A
  • Sphingosine backbone (an 18 carbon amino alcohol)
  • Acyl group (fatty acid chain) is amide-linked to the carbon-2 of the backbone
  • Variable group is attached to carbon-1 of backbone
238
Q

What are the different classes of sphingomyelin you need to need to know about?

A
  • Sphingomyelin
  • Gangliosides
  • Cerebrosides
239
Q

Describe the variable group of sphingomyelin (as a sphingolipid) and its role.

A
  • Variable group = Phosphocholine (or less commonly phosphoethanolamine) (meaning that sphingomyelins may also be classified as sphingophospholipids)
  • Role:
    • Electrical insulation in nerve fibres
    • Used in signal transduction
    • Apoptosis
240
Q

Describe the variable group of gangliosides (as a sphingolipid) and its role.

A
  • Variable group: Complex saccharides
  • Role:
    • Oligosaccharide groups on gangliosides act as markers in cellular recognition and cell-to-cell communication.
    • Also act as specific receptors for pituitary glycoprotein hormones and bacterial protein toxins.
241
Q

Describe the variable group of cerebrosides (as a sphingolipid) and its role.

A
  • Variable group: Glucose or galactose
  • Role:
    • Need to be turned over properly or may result in Gauchers
242
Q

What is the clinical relevance of sphingolipids?

A

The absence of specific sphingolipid degrading enzymes are know to cause a number of deadly, incurable genetic lysosomal storage diseases:

  • Tay-Sachs disease
  • Gaucher’s disease
  • Niemann-Pick disease.
243
Q

What is the major sterol in animals?

A

Cholesterol

244
Q

Describe the difference between cholesterol, sterols, steroids and steroid hormones.

A
  • Cholesterol is a type of sterol
  • Sterols are alcohol steroids
  • Steroid hormones are steroids that act as hormones
245
Q

Describe the structure of cholesterol.

A

Cholesterol is composed of:

  • Three 6-membered rings
  • One 5-carbon ring
  • Short aliphatic chain
  • Single hydroxyl group
246
Q

Describe the structure of bile acids and steroid hormones.

A

They are derivates of cholesterol, so they have a similar basic structure:

  • Three 6-membered rings
  • One 5-carbon ring
  • Short aliphatic chain
  • Single hydroxyl group
247
Q

Describe some of the important structural features of cholesterol.

A
  • The amphiphilic nature is conferred by the hydroxyl group
  • The hydroxyl group can be esterified in cholesteryl esters, leading to a highly nonpolar structure.
  • The molecules display a planar configuration which is rigid.
  • The compactness of sterols confer an important role for packing in membranes
248
Q

What can steroid hormones do?

A

Regulate transcription.

249
Q

Describe cholesterol synthesis and how it can be inhibited.

A
  • Acetyl CoA is converted to HMG CoA
  • HMG CoA is then converted to mevalonate by HMG CoA reductase
  • Mevalonate is then converted to cholesterol

Statins are often HMG CoA reductase inhibitors an therefore lower cholesterol levels.

250
Q

Give two examples of bile salts and their function.

A
  • Cholic acid and chenodeoxycholate
  • Bile salts & acids have higher hydrophilicity than cholesterol and are excreted into the intestine to emulsify lipids to aid digestion
251
Q

Name the 3 main roles of lipids in the cell and give an example of each.

A
  • Structural components of membranes -> Phospholipids, sphingolipids
  • Signaling molecules -> Phosphoinositides, arachidonic acid and steroid hormones
  • Fuels -> Triglycerides as high density energy sources
252
Q

What are glycoconjugates?

A
  • Mono-, oligo-, or polysaccharides attached to proteins or lipids.
  • i.e. Glycoproteins and glycolipids
253
Q

What are glycans?

A

The sugars WITHIN glycoproteins, glycolipids and proteoglycans.

254
Q

What are lectins?

A

Proteins that bind specifically to carbohydrates.

255
Q

Name the different types of glycoconjugates.

A
  • Those attached to lipids
  • Those attached to proteins through a nitrogen atom (N-linked glycan)
  • Those attached to proteins through an oxygen atom (O-linked glycan)
256
Q

Where are glycoconjugates (glycoproteins and glycolipids) found?

A
  • At the cell surface membrane.
  • Glycoproteins are also secreted into biological fluids and make up the insoluble ECM
257
Q

What is the difference in structure between a proteoglycan and a glycoprotein?

A
  • Proteoglycans have long chains with disaccharide as repeating structures.
  • Glycoproteins have short highly branched glycan chains with no repeating unit.
258
Q

What are some functions of glycoconjugates (glycoproteins and glycolipids)?

A
  • Intrinsic
    • Structural components, Cell walls -> ECM
    • Modifying protein properties -> Solubility and stability
  • Extrinsic
    • Directing trafficking of glycoconjugates
    • Mediating and modulating cell adhesion
    • Mediating and modulating signaling
259
Q

What type of sugar are glycans (the sugars in glycolipids and glycoproteins) usually?

A

They are usually monosaccharides, most commonly hexoses.

260
Q

What is the general formula for simple sugars?

A

Cn(H2O)n

261
Q

Give some examples of monosaccharides.

A
  • Glucose
  • Fructose
  • Galactose
262
Q

What type of hexose is glucose?

A

Aldose - it contains an aldehyde group.

263
Q

What type of hexose is fructose?

A

Ketose - it contains a ketone.

264
Q

What is the relevance of stereochemistry in hexoses?

A
  • Hexoses contain 4 chiral carbons
  • This means that there are 16 possible configurations for aldoses (with the aldehyde at the top) and 16 possible ketoses
  • There are 8 different aldosose, each with a D and L configuration, which depends on the OH on the final carbon
  • This means that D-glucose and D-galactose are very similar, differing only by the carbon-4 orientation -> This makes them epimers
  • On the other hand, D-glucose and L-glucose are enantiomers, since they are mirror images
265
Q

Name this a sugar.

A

D-galactose

266
Q

Name this sugar.

A

D-fructose

267
Q

Name this sugar.

A

D-glucose

268
Q

Name the two types of ring that a sugar can form.

A
  • Pyranose
  • Furanose
269
Q

Describe a pyranose ring and how it forms.

A
  • A hexagonal ring containing 5 carbons and 1 oxygen
  • Formed when the alcohol group on an aldose reacts with the aldehyde group
270
Q

Describe a furanose ring and how it forms.

A
  • A pentagonal ring containing 4 carbons and 1 oxygen
  • Formed when the alcohol group on an ketose reacts with the ketone group
271
Q

Describe anomeric carbons and the numbering of carbons in a pyranose and furanose ring.

A
  • The anomeric carbon is the one that is next to the O in the ring and that has an OH on it
  • In pyranose rings, it is C1, while it furanose rings it is C2
  • The carbons are numbered from the end of the carbon chain so that the anomeric carbon has the lower possible number
272
Q

Describe the importance of the atoms attached to the anomeric carbon.

A
  • If the OH points down (when the O is at the top of the ring), then the sugar is alpha
  • If the OH points up (when the O is at the top of the ring), then the sugar is beta
273
Q

Describe how sugars can acts as reducing sugars and which ones can do this.

A
  • Sugars that are open-chain with a free aldehyde group can act as reducing agents
  • This includes aldoses and ketoses that can easily convert to aldoses
  • The sugar reduces something while being oxidised -> Its carbonyl group is converted to a carboxyl group
  • This includes all monosaccharides
274
Q

Describe how blood sugar tests work.

A
  • They rely on the reducing properties of reducing sugars
  • Classically, Fehling’s solution:
    • Copper(II) ions of the complex are reduced to copper(I) ions
    • Red copper(I) oxide then precipitates out of the reaction mixture, which indicates a positive result i.e. that redox has taken place.
  • Modern tests involve either an electronic meters or colourimetric strips
    • Use glucose oxidase, that catalyses the oxidation of glucose to hydrogen peroxide and D-gluconolactone
    • Electronic meters measure the transfer of electrons
    • Colourimetric strips measure the hydrogen peroxide produced
275
Q

Draw the formation of a glycosidic bond.

A
276
Q

Describe the difference between an alpha and beta 1,4 glycosidic bond.

A
  • In alpha bonds, the two OH groups forming the bond are on the same side
  • In beta bonds, the two OH groups forming the bond are on different sides
277
Q

What are the main roles of carbohydrates?

A
  • Structural
  • Energy sources
  • Biosynthetic precursors
  • Signalling molecules
278
Q

When naming glycosidic bonds by the numbering of the carbons they link to, what two types do you need to know about?

A

1,4 and 1,6

279
Q

What sugars and bonds are found in glycogen, starch and cellulose?

A

All are homopolyers of glucose:

  • Glycogen -> α-1,4 glycosidic bonds
  • Starch -> α-1,4 glycosidic bonds
  • Cellulose -> β-1,4 glycosidic bonds.
280
Q

Where is cellulose found, what is its structure and what is its function?

A
  • It is found in the cell walls of plants
  • It is a linear polymer of glucose, joined by β-1,4 glycosidic bonds -> There are hydrogen bonds between fibres, giving strength against osmotic expansion
281
Q

What are the two types of starch and what are their structures?

A
  • Amylose -> Unbranched
  • Amylopectin -> Branched, but less than glycogen and longer branches
282
Q

Where is starch found, what is its structure and what is its function?

A
  • It is found in plant cells
  • It forms unbranched (amylose) or branched (amylopectin) homopolymers of glucose
    • Within branches there are α-1,4 glycosidic bonds
    • Branches are formed by α-1,6 glycosidic bonds
  • It is used for energy storage
283
Q

Where is glycogen found, what is its structure and what is its function?

A
  • It is found in animal cells
  • It forms unbranched homopolymers of glucose
    • Within branches there are α-1,4 glycosidic bonds
    • Branches are formed by α-1,6 glycosidic bonds
  • It is used for energy storage
284
Q

Why are homopolymers useful for energy storage?

A

They do not affect osmotic potential.

285
Q

Describe how glycogen and starch are broken down in the cell.

A

Broken down from the (4)-end via phosphorylase: more branches, the faster the breakdown.

286
Q

What are some examples of disaccharides?

A
  • Sucrose
  • Maltose
  • Lactose
287
Q

Give an example of the structural role of carbohydrates.

A
  • Glycosaminoglycans (GAGs) are carbohydrate polymers that are attached to ECM proteins to form proteoglycans.
  • These molecules have a net negative charge, which attract sodium ions and water, thus keeping the cells hydrated.
  • This also gives compression strength to tissues.
288
Q

Describe the structure and role of proteoglycans.

A
  • Proteoglycans are proteins that are heavily glycosylated.
  • The basic proteoglycan unit consists of a “core protein” with one or more covalently attached glycosaminoglycan (GAG) chains
  • Each GAG chain consists of alternating amino sugar derivatives and hexose derivatives
  • Several proteoglycan units can be arranged along a hyaluronic acid backbone, which acts as scaffold
  • The negative charge of the proteoglycan and the long carbohydrate chains help with stability and compression strength since they attract water to the ECM
289
Q

What are the different GAGs and what are they named after?

A

They are named after where they were first isolated:

  • Hyaluronic acid -> Hyaline membranes
  • Chondroitin sulphate -> Cartilage
  • Dermatan sulphate -> Skin
  • Keratin sulphate -> Skin
290
Q

What is the one unusual GAG and what makes it unusual?

A
  • Hyaluronic acid
  • It doesn’t form a proteoglycan with a core protein, but it acts as the very long backbone for the attachment of all of the other proteoglycans (non-covalently)
291
Q

What is the major proteoglycan in ECMs?

A

Aggrecan

292
Q

Describe the linkages in proteoglycan structures.

A
  • Hyaluronic does not form proteoglycans (only acts as backbone)
  • Chondroitin sulfate, dermatan sulfate -> O-linked glycosylation
  • Keratan sulfate -> N-linked glycosylation
293
Q

Where is each GAG found:

  • Hyaluronic acid
  • Chondroitin sulphate
  • Dermatan sulphate
  • Keratin sulphate
A
  • Hyaluronic acid -> Connective tissues, Skin, Cartilage, Synovial fluid
  • Chondroitin sulphate -> Cartilage, Cornea, Bone, Skin, Arteries
  • Dermatan sulphate -> Skin, Blood vessels, Heart valves
  • Keratin sulphate -> Cartilage, Cornea
294
Q

Give some examples of different proteoglycans in different parts of the body.

A
  • Aggrecan -> Cartilage
  • Neurocan -> Brain
  • Versican -> Blood vessels + Skin
295
Q

What amino acids allow for N-linked glycosylation and O-linked glycosylation?

A
  • N-linked glycosylation -> Asparagine
  • O-linked glycosylation -> Serine/threonine
296
Q

For N-linked glycosylation, what amino acid and sugar is typically involved? Is the link alpha or beta?

A
  • Amino acid = Asparagine
  • Sugar = N-acetylglucosamine (GlcNAc) (usually)
  • 𝛽 configuration
297
Q

Describe the synthesis of an N-linked glycan structure.

A
  1. Synthesis of dolichol-linked precursor oligosaccharide
    • Occurs in the cytoplasm
    • Dolichol is found on the outside of the ER membrane
    • Oligosaccharide is built up on dolichol phosphate (which is a long lipid made of repeating isoprene groups and an alcohol functional group) -> Dolichol phosphate acts as an anchor
    • Part of the synthesis occurs on the outside and part occurs on the inside of the ER
  2. En bloc transfer of precursor oligosaccharide to protein
    • Occurs inside the ER during translation
    • Oligosaccharyl transferase transfers the oligosaccharide to the asparagine residue of the target protein at a target sequence
  3. Processing of the oligosaccharide
    • Occurs inside the ER and then inside the Golgi apparatus
    • Exoglycosidases (cleave sugars from non-reducing end)
    • Glycosidase I removes terminal 𝛼1-2 linked glucose, whereas glucosidase II cleaves 𝛼1-3
    • Followed by a series of mannosidases, that remove mannose linked 𝛼1-2
    • Glycans containing between 5 and 9 mannose sugars are called high mannose oligosaccharides.
    • Finally, complex glycans are just built on this core that consists of just three mannose residues and two GlcNAc residues.
298
Q

Describe how blood type is determined and what the Bombay phenotype is.

A
  • Blood type depends on the sugars in N-linked glycans attached to cell-surface proteins
  • The antigenic glycans are built up on the ends of polylactosamine chains by fucosyltransferase -> This generates an H antigen.
  • Individuals with the O blood group only contain this sugar.
  • In A type individuals, a GalNAc residue is added to the terminal galactose, while in B type individuals, a Gal residue is appended.
  • In AB type both modifications are present.
  • Bombay phenotype -> Individuals lacking the genes for the fucosyltransferase make antibodies to the H antigen -> This means that they cannot receive any ABO blood groups.
299
Q

What are the main types of O-linked proteins?

A
  • Proteoglycans
  • Mucins
  • Antibodies have small amounts of O-linked sugars at their hinges
300
Q

What are mucins and what is their function?

A
  • Heavily O-glycosylated proteins
  • Their role is to retain water and form gels, which is useful as a barrier and for lubrication
  • Aside from this, transmembrane mucins have a receptor-like structure that is similar to immune receptors. The highly glycosylated extracellular domain of transmembrane mucins has a barrier function whereas the intracellular domain can be phosphorylated and activate signal transduction pathways. The extracellular domain of transmembrane mucins can bind bacteria and can be shed from the epithelial surface. Shedding of the extracellular domain could be an activation signal that leads to phosphorylation of the intracellular domain and activation of mucin-specific signaling pathways that alter inflammatory responses, epithelial cell adhesion, differentiation, and apoptosis.
301
Q

How does the process of O-linked glycosylation differ from N-linked glycosylation?

A

Similarities:

  • Utilises glycosyltransferases analagous to those in N-linked pathways

Differences:

  • All sugars are added sequentially, starting with the first GalNAc residue attached to the Ser/Thr. (there is no preferred or en bloc transfer event).
  • There are no simple target sequences for O-linked glycosylation analagous to the Asn-X-S/T sequence.
  • Specificity comes from recognition of the target protein by the oligosaccaharide transferase.
  • O-linked glycosylation takes place in the Golgi apparatus post-translationally (i.e. not linked to protein translation).
302
Q

Name some of the roles of glycoproteins.

A
303
Q

Describe how glycolipids function as anchors.

A
  • Anchoring proteins to lipid membranes by covalent attachment to fatty acids and lipids is an important alternative to anchoring through transmembrane helices
  • In mammalian cells >100 proteins are known to be attached to the membrane through the use of membrane anchors
  • Glycolipids attached to proteins are usually known as glycosylphosphatidyl inositol (GPI) anchors
  • The glycan that bridges between the protein and the lipid is attached to the inositol head group of the lipid.
  • For example, in humans AChE is tethered using a GPI anchor.
  • The linkage may be cut to release the protein.
304
Q

What are lectins and what are the different types?

A

They are proteins that bind to sugar molecules:

  • C-type lectins (sometimes referred to as selectins) -> Participate cell adhesion
  • L-selectins on the surface of lymphocytes -> Binds to counter receptors on endothelial cells
  • P and E selectins -> Involved in the migration of neutrophils to sites of inflammation
305
Q

Give some examples of molecules that carbohydrates are involved in the synthesis of.

A
  • Nucleotides
  • Fatty acids
  • Amino acids

(Add some more flashcards on this?)

306
Q

What are some of the functions of biological membranes?

A
  • Barrier
  • Selective permeability
  • Response to external stimuli
  • Electrical excitability
  • Energy conversion processes
  • Signalling to external environment
307
Q

What are some common features of biological membranes?

A
  • Membranes are sheet-like structure only a few molecules thick (50 - 70 Angstroms; 5-7nm)
  • Membranes form self-repairing closed boundaries between compartments
  • Membranes contain proteins embedded in a phospholipid bilayer
  • Distinctive functions of membranes are mediated by the membrane proteins
  • Membranes exist as non-covalent assemblies, held together by co-operative non-covalent forces
  • Membranes are asymmetric - the two faces of the membrane differ in composition both for protein (absolute asymmetry) and lipid (relative asymmetry)
  • Membranes form a highly fluid structure - “a two-dimensional solution of oriented proteins and lipids”
  • Phospholipids may cluster to form patches or ‘rafts’ with distinct protein composition and properties
308
Q

Describe compartmentation within the cell.

A
  • There is the classic form of compartmentation within organelles in the cell
  • There is also dynamic membrane-free compartmentalisation by phase separation -> Examples include lipid droplets, stress granules and the nucleolus within the nucleus
309
Q

What is the cytoskeleton?

A

Complex networks of protein filaments extending throughout the cytoplasm.

310
Q

See flashcards on the cytoskeleton in the OB deck 1.

A

Do it.

311
Q

By what process is communication between organelles enabled?

A

Vesicular trafficking -> It prevents loss of organelle identity of leakage into the cytoplasm.

312
Q

What are the main vesicle trafficking route you need to know about?

A

From endoplasmic reticulum to Golgi apparatus, then to the plasmalemma or to lysosomes.

313
Q

Describe the vesicle trafficking route that comes from the endoplasmic reticulum.

A
  • Endoplasmic reticulum passes vesicles to the Golgi apparatus
  • From the Golgi, the vesicles can go to the cell membrane or to lysosomes (for degradation)
314
Q

What are the two functions of vesicular trafficking to the cell membrane?

A
  1. Adds material to the plasmalemma
  2. Allows secretion into the extracellular space
315
Q

What are the two forms of vesicular secretion from a cell?

A
  • Constitutive -> When secretion is continuous, regardless of external factors or signals
  • Regulated
316
Q

What is receptor-mediated endocytosis?

A
  • A process by which cells absorb metabolites, hormones, proteins by the inward budding of the plasma membrane (invagination).
  • This process forms vesicles containing the absorbed substances and is strictly mediated by receptors on the surface of the cell.
  • Only the receptor-specific substances can enter the cell through this process.
317
Q

Describe the pathway of materials endocytosed into vesicles.

A
  • Join early endosomes
  • These become late endosomes and fuse with lysosomes
  • This is where the material is processed
318
Q

What is transcytosis?

A

A type of transcellular transport in which various macromolecules are transported across the interior of a cell. Macromolecules are captured in vesicles on one side of the cell, drawn across the cell, and ejected on the other side.

319
Q

What is used to direct the secretion of a newly synthesised protein in vesicles?

A

Signal sequence -> A short peptide (usually 16-30 amino acids long) present at the N-terminus of the majority of newly synthesized proteins that are destined towards the secretory pathway.

320
Q

Draw the cell cycle.

A

NOTE: The arrow out of the cycle points to G0, for non-cycling cells.

321
Q

What happens in the S phase of the cell cycle?

A

DNA replication

322
Q

What happens in the M phase of the cell cycle?

A

Mitosis

323
Q

Do G1 and G2 phases of the cell cycle involve an specific events?

A

No, they tend to involve growth, but no specific events must happen in them.

324
Q

What are the stages of mitosis you need to know about?

A
  • Prophase
  • Metaphase
  • Anaphase
  • Telophase
  • Cytokinesis
325
Q

What happens at the start of mitosis?

A

Appearance of the chromosomes and separation of the chromatids

326
Q

Draw the stages of mitosis.

A

NOTE: Don’t think you need to know about prometaphase.

327
Q

What organism is very good for studying the cell cycle?

A

Yeast

328
Q

What are cdc genes?

A

Genes that code for proteins that regulate the cell division cycle. They regulate the movement between mitosis, interphase, etc.

329
Q

How can cdc genes be identified? [EXTRA?]

A

Cloning by functional complementation

330
Q

What is an example of an important cdc gene?

A

cdc2

331
Q

What does the cdc2 gene encode and what does it do?

A

Encodes a cyclin-dependent protein kinase (CDK):

  • Activity totally dependent on association with a cyclin partner protein
  • Phosphorylates numerous protein substrates to drive cell cycle transitions
332
Q

Draw the cell cycle showing the involvement of CDK proteins. [EXTRA?]

A
333
Q

Draw the main checkpoints in the cell cycle.

A
334
Q

What is ataxia-telangiectasia (A-T)?

[EXTRA?]

A

A condition characterised by no cell cycle response to the chromosomal breakages.

335
Q

Draw the stages of meiosis.

A
336
Q

What does meiosis produce?

A

Haploid gametes

337
Q

What is another name for meiosis I?

A

Reductive division

338
Q

What cells undergo meiosis I?

A

Primary gametocytes

339
Q

When does crossing over of chromatids (exchange of maternal and paternal genes) occur in meiosis?

A

Prophase I

340
Q

When does independent segregation occur in meiosis?

A

Anaphase I

341
Q

Describe the stages of meiosis I.

A
  • Follows normal S phase in primary gametocyte
  • Prophase I:
    • Pairing of homologous chromosomes
    • Chromatids cross-over (exchange of maternal and paternal genes)
  • Metaphase I
  • Anaphase I:
    • Maternal and paternal chromosomes separate at random to form daughter nuclei
  • Telophase I
342
Q

What is the product of meiosis I?

A

Two secondary gametocytes

343
Q

Describe what happens in meiosis II.

A

It essentially resembles mitosis.

344
Q

Is there an S phase between meiosis I and II?

A

No

345
Q

How many gametes can be produced from a primary gametocyte?

A

4

346
Q

Draw the process of oogenesis, including where the cell cycle is arrested.

A
347
Q

How does the likelihood of meiotic segregation errors vary with maternal age?

A

It increases with age.

348
Q

Name the 3 ways in which meiosis and sexual behaviour generates diversity.

A
  • Crossing-over during prophase I
  • Independent assortment during meiosis I
  • Different male and female gametes fuse on fertilization
349
Q

What are constitutive and facultative heterochromatin?

A
  • Facultative heterochromatin -> The result of genes that are silenced through a mechanism such as histone deacetylation
  • Constitutive heterochromatin -> Active DNA
350
Q

What are the main PTMs mentioned in the spec?

A
  • Disulfide bonding
  • Cross-linking
  • Peptidolysis
  • Glycosylation
  • Phosphorylation
  • Adenylation
  • Farnesylation
351
Q

What are the main roles of PTMs?

A
  • Regulation
  • Targeting
  • Turnover
  • Structural
352
Q

Which amino acids can be glycosylated?

A
  • N-linked:
    • Asparagine
    • Arginine side-chains
  • O-linked:
    • Serine
    • Threonine
    • Tyrosine
    • Hydroxylysine
    • Hydroxyproline
353
Q

What amino acids can be phosphorylated?

A
  • Threonine
  • Serine
  • Tyrosine
354
Q

What is adenylation?

A
  • The process of attaching an AMP molecule to a protein side chain by covalent bonding.
  • a.k.a. AMPylation
355
Q

Which amino acids can be adenylated?

A
  • Tyrosine
  • Threonine
  • Serine
356
Q

What does adenylation do?

A

Affects various protein properties, including:

  • Stability
  • Enzymatic activity
  • Co-factor binding
357
Q

What is farnesylation?

A

Addition of an isoprenyl group to an amino acid.

358
Q

What does farnesylation do?

A

Important to mediate protein–protein interactions and protein–membrane interactions

359
Q

Which amino acids can be farnesylated?

A

Cysteine