1 and 2 Flashcards

1
Q

List the Drug Discovery Pathway?

A

Biology 1 –> HTS –> Med Chem/DMPK –> Biology 2 –> Clinical trials

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2
Q

What is HTS and DMPK?

A

HTS = High throughput Screening

DMPK = Drug Metabolism Pharmacokinetics

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3
Q

What is the Pre-clinical stage?

A

Biology 1, HTS, Med Chem/DMPK and Biology 2

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4
Q

Why aren’t all lead compounds used as a drug?

A

Most lead compounds are unsuitable for clinical use for a variety of reasons:

  • Not active enough
  • Have serious or undesired side effects
  • Not easily administered to patients → not orally active
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5
Q

How can we develop drugs from leads?

A

By changing the structure.

Structural changes to a lead compound often alter pharmacological action and can improve a particular activity or eliminate side effects

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6
Q

What do similar molecules tend to have?

A

Structurally similar molecules tend to have similar properties → neighbourhood behaviour.

E.g. Codeine, Morphine and Heroin

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7
Q

What is ‘STRUCTURE-ACTIVITY RELATIONSHIP’ (SAR)?

A

The correlation of structure with biological activity

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8
Q

What is the aim of SAR studies?

A
  • Determine which parts of the lead molecule are essential for biological activity and which parts cause the undesired side effects
  • Develop an analogue of the lead compound that has the best combination of therapeutic properties

Identifies all important binding groups in the lead compound - Pharmacophore

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9
Q

What is a pharmacophore?

A

A pharmacophore contains only the relevant groups that interact with a receptor and are responsible for the activity

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10
Q

How to use SAR’ s to determine the pharmacophores?

A

IDENTIFICATION OF A LEAD STRUCTURE

IDENTIFICATION OF POSSIBLE DRUG TARGET BINDING GROUPS

SYNTHESIS OF A SERIES OF ANALOGUES WHERE ONE BINDING GROUP IS REMOVED

TEST ALL ANALOGUES FOR BIOLOGICAL ACTIVITY

IDENTIFICATION OF PHARMACOPHORE

So a single binding group is modified or removed

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11
Q

Explain the results of SAR studies?

A

If bioactivity is much lower after modification we know that functional group is important and all analogues must contain it.

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12
Q

What are the three different ways in which a potential binding group can bind to a target?

A

H-bonding: This is important for groups possessing electron defficient hydrogens, e.g., hydroxyl and amino groups

Ionic binding: Important for groups that can form cations or anions in vivo, e.g., amino groups

Van der Waals / Hydrophobic contacts: Important for hydrophobic groups that can lie close to and interact with hydrophobic groups in a target, e.g., aromatic rings, double bonds

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13
Q

What does ligand hydrophobicity and hydrogen bonding give?

A

Ligand hydrophobicity gives affinity, whereas hydrogen bonding gives specificity.

It is generally accepted that high-affinity ligands bind in low-energy confirmations.

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14
Q

What do Biochemical systems exhibit?

A

Biochemical systems exhibit enthalpy-entropy compensation, where increased bonding is offset by an entropic penalty, reducing the magnitude of change in affinity.

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15
Q

Explain how hydroxyl groups are involved in hydrogen bonding?

A
  1. Via the hydrogen atom, by interaction with a carbonyl group (or other lone pair donor) on the receptor
  2. Via the oxygen atom by interaction with an electron deficient hydrogen atom on the receptor
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16
Q

Explain how a hydroxyl group can be removed?

A

An hydroxyl group can be totally removed by conversion to a mesylate or tosylate followed by reduction with LiAlH4.

17
Q

What are amino groups involved in and how is this prevented?

A

Amines are involved in H-bonding and ionic bonding to groups on the receptor.

Conversion of the amine to an amide will prevent involvement of the lone pairs in hydrogen bonding, and will also prevent ion formation.

18
Q

How are Tertiary amines dealkylated? And why?

A

This is usually done using cyanogen bromide – the von Braun reaction.

Because they have no hydrogen attached, so hydrogen bonding cannot happen as hydrogen is needed for this bonding to occur.

19
Q

What are Aromatic rings involved in?

A

Usually involved in van der Waals interactions with hydrophobic parts of a target site.

Aromatic rings can interact with flat hydrophobic parts of a receptor → π-π stacking.

20
Q

Where are VDW strongest?

How is this weakened in Aromatic rings?

A

Van der Waals interactions are cumulative and are strongest between moieties that can approach each other closely.

The aromatic ring may be hydrogenated to a cyclohexane - the structure is no longer flat and van der Waals interactions with the receptor will now be weaker.

21
Q

What are double bonds involved in?

What weakens this?

A

Van der Waals interactions with hydrophobic regions of a receptor.

Reduction will weaken the interaction as the alkane cannot approach the receptor surface as closely.

22
Q

What are ketones involved in?

How does this work and how is this interaction weakened?

A

H-bonding or dipole-dipole interactions with the target.

The ketone will align to interact with a dipole moment in the target.

Reduction to an alcohol will weaken both types of interaction. The geometry and hence alignment of the functional group will change.

23
Q

What are amides involved in?

How is this weakened/disrupted?

A

H-bonding of the carbonyl oxygen.

Reduction will disrupt H-bonding involving the carbonyl oxygen.

24
Q

What is an Isostere?

Why are they important?

A

An atom or group of atoms having identical numbers of outer shell electrons.

Replacement of a potential binding group with a classical isostere is a useful way of determining whether it is important or not.

25
Q

What are non-classical isosteres?

A

Isosteres that differ by one parameter, e.g., size or electronegativity

26
Q

What are the different isosteres?

A
  • SH, NH2 , CH3 are isosteres of OH
  • S, NH, CH2 are isosteres of O
  • Replace OH with CH3 can be used to determine if H-bonding is taking place
  • Replace OH with NH2 , H-bonding remains