07 Pedigrees and Risk Calculation Flashcards

1
Q

What are some good reasons to draw a pedigree?

A

It’s the first step of genetic risk assessment.
It’s easy to visualise.
It’s an efficient way to collect family history.
It builds rapport.
It can reveal psychosocial issues such as comms barriers in the family.

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2
Q

What does a slash mean in a pedigree?

A

Someone is deceased

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3
Q

What does a shaded in shape mean in a pedigree?

A

An affected family member

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4
Q

What does a square mean in a pedigree?

A

A male

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5
Q

What does a circle mean in a pedigree?

A

A female

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6
Q

How would you draw a fetus of unknown sex in a pedigree?

A

A diamond and say how many weeks old

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7
Q

How would you draw a stillbirth on a pedigree?

A

Either a diamond, square or circle, with a slash through it, and the letters SB.

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8
Q

How would you draw the distinction between a termination of pregnancy and a miscarriage/spontaneous abortion on a pedigree?

A

A termination of a pregnancy is with a slash. A miscarriage or spontaneous abortion has no slash. Both would be triangles.

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9
Q

What is a dot inside a shape on a pedigree?

A

A carrier

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10
Q

What does it mean when sections of a shape are shaded in?

A

Different aspects of the phenotype. Maybe Ovarian OR breast cancer.

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11
Q

How are fraternal and identical twins differentiated on a pedigree?

A

Both sets are draw with diagonal lines going down. Identical twins have a horizontal line between them connecting them, fraternal do not.

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12
Q

How are asymptomic/presymptomatic carriers drawn on a pedigree?

A

A horizontal line down through the middle of the shape.

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13
Q

How are consanguinous couples shown on a pedigree?

A

two horizontal lines connecting them.

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14
Q

What do you often put on a pedigree next to each person’s icon?

A

DOB and name

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15
Q

What generally causes an autosomal recessive inheritance?

A

A biallelic LOF

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16
Q

What pattern do AR disorders show on a pedigree?

A

Horizontal pattern - siblings affected, neither parent

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17
Q

What’s the chance of two AR carriers having an affected child?

A

1 in 4

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18
Q

Where might an AR disease show a pseudo-dominant inheritance pattern?

A

In consanguinous families.

19
Q

What pattern do autosomal dominant disorders show as on a pedigree?

A

Vertical. Grandparent, parent, child affected.

20
Q

What’s the chance of an adult with an AD condition having an affected child?

A

1 in 2

21
Q

What can the genetic mechanism be behind autosomal dominant disorders?

A

hapolinsufficiency, or GOF, or dominant negative effects (The mutant protein affects the function of the wild type protein).

22
Q

What is penetrance of AD conditions?

A

That those carrying the mutation don’t always show the phenotype. This may be a set percentage, or may be age related.

23
Q

What is the concept of expressivity with AD conditions?

A

It’s the degree to which people with an AD condition experience differing levels of severity of that condition

24
Q

What pattern do X-linked disorders show on pedigrees?

A

Knights move patterns. Affected males with affected uncles

25
Q

With X linked conditions males are _____ and females are usually _____

A

males are affected, and females are usually carriers

26
Q

For X linked conditions Sons of a female character have a 1 in ____ chance of being affected and daughters have a 1 in ____ chance of being a carrier. For an affected male, their sons have a 1 in _____ chance of being affected and a 1 in _____ chance of being a carrier

A

1 in 2
1 in 2
1 in 1
1 in 1

27
Q

What pattern of inheritance do mitochondrial disorders show on a pedigree?

A

Vertical pattern

28
Q

What is heteroplasmy in relation to mitochondrial disorders?

A

How there will be an extremely variable phenotype based on the proportion of affected mitochondria

29
Q

How are mitochondrial disorders passed on?

A

Through mothers

30
Q

The neurodegenerative disease Huntington’s shows what feature of inheritance?

A

It’s autosomal dominant. But has age related penetrance. And it shows anticipation.

31
Q

Freidrich’s ataxia has what inheritance pattern?

A

Autosomal recessive

32
Q

If someone has a sibling with Friedrich’s ataxia, an early onset disorder, what’s the chance of that person being a carrier?

A

2/3 chance. Because we’ve ruled out them being affected, so there’s only 3 options left.

33
Q

A man has a sibling with cystic fibrosis. What calculation do you need to do to work out the chance of him having an affected child?

A

His chance of being a carrier (2/3) * Chance of mum being a carrier from general population rate * 1/4 inheritance pattern

34
Q

If X-linked haemophilia A is in a family, what might be done during a pregnancy?

A

An amniocentesis at 34 weeks to genotype the baby to inform how the delivery should go.

35
Q

What are the two Hardy Weinberg equations?

A

P+Q=1 P2+2PQ+Q2=1

36
Q

In Hardy Weinberg equations when working with rare disorders, P is nearly always equal to what?

A

1

37
Q

Hardy Weinberg tells you what?

A

The proportion of homozygotes (for each allele) and heterozygotes in the population

38
Q

What would hardy weinberg with 3 alleles be?

A

P+Q+R=1 P2+2PQ+Q2+2QR+R2+2PR =

39
Q

What are males and females in hardy weinberg with x linked disorders?

A

Males are P or Q. Females are P2, 2PQ, or Q2

40
Q

Why doesn’t simple hardy weinberg work with consanguinity?

A

You’ll over estimate the incidence in the population and thus over estimate carrier frequency

41
Q

What are the basics of Bayes theorem?

A

You combine risk information that you know from different sources, then modify the probability based on conditions.
So you work out the Prior risk due to population risk or family history. THEN add additional information regarding the Conditional probablility (e.g. test results, penetrance, unaffected children/siblings)

42
Q

Prior risk X conditional likelihood = ?

A

Joint/Final risk

43
Q

A man has a parent with a dominant allele for a disease with incomplete penetrance of 90%. This man has no symptoms. So what’s the risk of him being a carrier using Bayes?

A

Well he has a 1/2 chance of having the allele as his prior risk from his parent. Then if he doesn’t have symptoms that means he’s in the 1 in 10 people without symptoms. So the joint risk is 1/2*1/10 =1/20. But he could be aa with no symptoms, which would just be a 1 in 2 chance. So 1/20 and 1/2 are our two options. So the chance of him being Aa/Aa+aa = 0.05/(0.05+0.50) = 0.5/0.55 = 1 in 11 chance.