01-Simple Harmonic Motion Flashcards

1
Q

Definition of Simple Harmonic Motion (SHM)

A

Oscillatory motion in which acceleration is directly proportional to the displacement and always directed towards the equilibrium position.

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1
Q

In SMH, in which direction is the body accelerating?

A

Towards the centre of the motion (except at the centre of the motion where the acceleration is zero).

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2
Q

Time Period & Frequency of the oscillation:

A

-A restoring force tries to return system to equilibrium.
-The system has inertia and overshoots equilibrium position
-The object oscillates with simple harmonic motion because its acceleration is proportional to the displacement from equilibrium and always acts towards equilibrium .

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3
Q

What is Damping?

A

The dissipation of energy over time

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4
Q

Types of Damping

A
  1. Light damping: amplitude of oscillation is reduced gradually.
  2. Critical Damping: returns to its equilibrium position in the shortest possible.
  3. Heavy Damping: returns to the equilibrium position very slowly.
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5
Q

Simple Harmonic Motion (SHM) formula

A

π‘Ž π›Όβˆ’π‘₯, where a ≑ acceleration; x ≑ displacement
π‘Ž= βˆ’ π‘π‘œπ‘›π‘ π‘‘π‘Žπ‘›π‘‘ Γ— π‘‘π‘–π‘ π‘π‘™π‘Žπ‘π‘’π‘šπ‘’π‘›π‘‘ π‘₯.

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6
Q

Time Period & Frequency of the oscillation formula

A

πœ”=2πœ‹/𝑇 π‘œπ‘Ÿ 2πœ‹π‘“
T=1/𝑓, 𝑓=1/T

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7
Q

Mathematical expression for displacement in SHM formula

A

-π‘Ž=βˆ’πœ”^2 π‘₯
-πœ”= 2πœ‹π‘“
-If x =+A when t =0 at zero velocity: π‘₯ =𝐴 cos⁑( πœ”t)
-If the value of x is 0 when t =0: π‘₯ =𝐴 𝑠𝑖 𝑛⁑( πœ”t)

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8
Q

Time Period in a mass-spring system formula

A

-Hook’s Law, 𝐹 = π‘˜π‘₯
-Newton’s 2nd Law, F= ma, π‘Ž = βˆ’(π‘Ÿπ‘’π‘ π‘‘π‘œπ‘Ÿπ‘–π‘›π‘” π‘“π‘œπ‘Ÿπ‘π‘’)/π‘šπ‘Žπ‘ π‘ = (βˆ’π‘˜π‘₯)/π‘š
-Combining those two equations, we get γ€–π‘šπœ”γ€—^2 π‘₯=π‘˜π‘₯; π‘šπœ”^2=π‘˜; πœ”=√(π‘˜/π‘š)
2πœ‹/𝑇=√(π‘˜/π‘š), 𝑇=2πœ‹βˆš(π‘š/π‘˜)

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9
Q

Time Period in a pendulum formula

A

-π‘šπ‘”π‘π‘œπ‘ πœƒ perpendicular to the path or the bob.
-π‘šπ‘”π‘ π‘–π‘›πœƒ along the path towards the equilibrium position.
-The restoring force, 𝐹=βˆ’π‘šπ‘”π‘ π‘–π‘›πœƒ
-Acceleration, π‘Ž=𝐹/π‘š =βˆ’π‘šπ‘”sinπœƒ/π‘š = βˆ’π‘”π‘ π‘–π‘›πœƒ
-ΞΈ does not exceed approximately 10Β°, π‘ π‘–π‘›πœƒ=𝑠/𝐿 and π‘Ž =βˆ’π‘”/𝐿 𝑠=βˆ’πœ”^2 𝑠, π‘€β„Žπ‘’π‘Ÿπ‘’ πœ”^2=𝑔/𝐿
-2πœ‹/𝑇=√(𝑔/𝐿), 𝑇=2πœ‹βˆš(𝐿/𝑔)

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10
Q

The energy equation in SHM formula

A

-The potential energy Ep changes with displacement x from equilibrium, in accordance with the equation
-𝐸𝑝 =1/2 π‘˜π‘₯^2
-𝐸T=1/2 π‘˜π΄^2
-𝐸𝑇=𝐸𝐾+𝐸𝑃
-πΈπ‘˜=πΈπ‘‡βˆ’πΈπ‘ƒ=1/2 π‘˜ (𝐴^2βˆ’π‘₯^2 )

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