01-Simple Harmonic Motion Flashcards

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1
Q

Definition of Simple Harmonic Motion (SHM)

A

Oscillatory motion in which acceleration is directly proportional to the displacement and always directed towards the equilibrium position.

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1
Q

In SMH, in which direction is the body accelerating?

A

Towards the centre of the motion (except at the centre of the motion where the acceleration is zero).

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2
Q

Time Period & Frequency of the oscillation:

A

-A restoring force tries to return system to equilibrium.
-The system has inertia and overshoots equilibrium position
-The object oscillates with simple harmonic motion because its acceleration is proportional to the displacement from equilibrium and always acts towards equilibrium .

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3
Q

What is Damping?

A

The dissipation of energy over time

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4
Q

Types of Damping

A
  1. Light damping: amplitude of oscillation is reduced gradually.
  2. Critical Damping: returns to its equilibrium position in the shortest possible.
  3. Heavy Damping: returns to the equilibrium position very slowly.
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5
Q

Simple Harmonic Motion (SHM) formula

A

๐‘Ž ๐›ผโˆ’๐‘ฅ, where a โ‰ก acceleration; x โ‰ก displacement
๐‘Ž= โˆ’ ๐‘๐‘œ๐‘›๐‘ ๐‘ก๐‘Ž๐‘›๐‘ก ร— ๐‘‘๐‘–๐‘ ๐‘๐‘™๐‘Ž๐‘๐‘’๐‘š๐‘’๐‘›๐‘ก ๐‘ฅ.

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6
Q

Time Period & Frequency of the oscillation formula

A

๐œ”=2๐œ‹/๐‘‡ ๐‘œ๐‘Ÿ 2๐œ‹๐‘“
T=1/๐‘“, ๐‘“=1/T

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7
Q

Mathematical expression for displacement in SHM formula

A

-๐‘Ž=โˆ’๐œ”^2 ๐‘ฅ
-๐œ”= 2๐œ‹๐‘“
-If x =+A when t =0 at zero velocity: ๐‘ฅ =๐ด cosโก( ๐œ”t)
-If the value of x is 0 when t =0: ๐‘ฅ =๐ด ๐‘ ๐‘– ๐‘›โก( ๐œ”t)

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8
Q

Time Period in a mass-spring system formula

A

-Hookโ€™s Law, ๐น = ๐‘˜๐‘ฅ
-Newtonโ€™s 2nd Law, F= ma, ๐‘Ž = โˆ’(๐‘Ÿ๐‘’๐‘ ๐‘ก๐‘œ๐‘Ÿ๐‘–๐‘›๐‘” ๐‘“๐‘œ๐‘Ÿ๐‘๐‘’)/๐‘š๐‘Ž๐‘ ๐‘ = (โˆ’๐‘˜๐‘ฅ)/๐‘š
-Combining those two equations, we get ใ€–๐‘š๐œ”ใ€—^2 ๐‘ฅ=๐‘˜๐‘ฅ; ๐‘š๐œ”^2=๐‘˜; ๐œ”=โˆš(๐‘˜/๐‘š)
2๐œ‹/๐‘‡=โˆš(๐‘˜/๐‘š), ๐‘‡=2๐œ‹โˆš(๐‘š/๐‘˜)

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9
Q

Time Period in a pendulum formula

A

-๐‘š๐‘”๐‘๐‘œ๐‘ ๐œƒ perpendicular to the path or the bob.
-๐‘š๐‘”๐‘ ๐‘–๐‘›๐œƒ along the path towards the equilibrium position.
-The restoring force, ๐น=โˆ’๐‘š๐‘”๐‘ ๐‘–๐‘›๐œƒ
-Acceleration, ๐‘Ž=๐น/๐‘š =โˆ’๐‘š๐‘”sin๐œƒ/๐‘š = โˆ’๐‘”๐‘ ๐‘–๐‘›๐œƒ
-ฮธ does not exceed approximately 10ยฐ, ๐‘ ๐‘–๐‘›๐œƒ=๐‘ /๐ฟ and ๐‘Ž =โˆ’๐‘”/๐ฟ ๐‘ =โˆ’๐œ”^2 ๐‘ , ๐‘คโ„Ž๐‘’๐‘Ÿ๐‘’ ๐œ”^2=๐‘”/๐ฟ
-2๐œ‹/๐‘‡=โˆš(๐‘”/๐ฟ), ๐‘‡=2๐œ‹โˆš(๐ฟ/๐‘”)

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10
Q

The energy equation in SHM formula

A

-The potential energy Ep changes with displacement x from equilibrium, in accordance with the equation
-๐ธ๐‘ =1/2 ๐‘˜๐‘ฅ^2
-๐ธT=1/2 ๐‘˜๐ด^2
-๐ธ๐‘‡=๐ธ๐พ+๐ธ๐‘ƒ
-๐ธ๐‘˜=๐ธ๐‘‡โˆ’๐ธ๐‘ƒ=1/2 ๐‘˜ (๐ด^2โˆ’๐‘ฅ^2 )

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