... Flashcards
area of sector
0.5*r(^2)θ
area of segment
0.5r^2 (θ − sin(θ))
arc length
rθ
area of trapezium
(a+b)/2 *h
cos2A
cos(^2)A-sin(^2)A
2cos(^2)A-1
1-2sin(^2)A
sin2A
2sinAcosA
tan2A
(2tanA)/(1-tan(^2)A)
derivative of a^(kx)
a(^kx) k ln a
integral of f(AX+B)
1/a f(ax+b)
prove the sum of the first n terms of an arithmetic series is 1/2n(2a+(n-1)d)
- Sn= a, a+d, a+2d+…….+ a+(n-2)d + a+(n-1)d
- reverse sequence(Sn): a+(n-1)d + a+(n-2)d +………+ a+2d + a+d + a
- add the two sequences: 2Sn= n(2a+(n-1)d)
- divide by 2: Sn= n/2 (2a+(n-1)d)
Proof of geometric series
(1) Sn= a+ ar +ar2+ ar3+…..+ar(n-2)+ ar(n-1)
(2) rSn= ar+ ar2+ ar3 +…..+ ar(n-1) + ar(n)
(1)-(2) Sn-rSn = a-ar(n)
Sn(1-r)= a(1-r(n))
Sn= a(1-r(n))/1-r
Volume of sphere
4/3pi r^2
prove the first principles, that the derivative of sin x is cos x
f’(x)= (f(x+h)-f(x))/h
(sin(x+h)-sin(x))/h
(sinx cosh + cosx sinh - sin x)/ h
(cos h -1)/h)sinx + (sin h)/h)cosx
cos h-1/ h ——> 0
sin h/h——>1
0sin x +1 cosx
=cos x
how to convert degrees to radians
multiply value of degrees by pi/180
proof of infinite primes
Assumption: there are a finite number of prime numbers,
p1, p2, p3, up to pn
. Let X= (p1* p2* p3……Pn)+1
None of the prime numbers are a factor of X as they all leave a remainder of 1 when X is divided by them.
But X must have at least one prime factor.
This is a contradiction