Motion in a straight line Flashcards
Displacement in nth second
Sn = u + a/2(2n - 1)
Area under vt gives
displacement
Area under vt gives
distance
Area under at gives
change in V
at height H, V =
√2gH
at height H, V & time of fall is independant of
mass
Time of fall
t = √(2H/g)
When obj is thrown upwards, a =
-g
At max H, V =
0
H(max)
u^2/2g
Time of flight
T = 2t t = time of fall
S =
αβt^2/2[α+β] where α, β are acc at time t1, t2
tanα =
Bsinθ/ A + Bcosθ
if |A| = |B|, then |R| =
2Acosθ/2 = |A+B|
if |A| = |B|, then |A-B| =
2Asinθ/2
Fcosθ =
ma
At max height Vy =
0
Eqn of trajectory
y = xtanθ - gx^2/2u^2cos^θ
Time of flight T =
2usinθ/g
Max H =
u^2sin^2θ/2g
Horizontal range R =
u^2sin2θ/g
R =
= 4H/tanθ
= T^2g/2tanθ
H =
T^2 g/8
When θ = 90, R =
0, Hmax = u^2/2g
When θ = 45, R =
Rmax = u^/g Hmax = Rmax/4
change in momentum of projectile
Horizontal momentum remains const
F =
mrω^2
