Lecture 5

Question 1

Convolution

Answer 1

Describes the effect of one signal on another

Question 2

Correlation

Answer 2

Describes the similarity of two signals

Question 3

The image intensity distribution is the

Answer 3

convolution of this point source and the point spread function

Question 4

Convolution : Point Spread Function

Answer 4

O(x2) = (0 ∫ ∞) I(x1) PSF(x2-x1)dx1

where O(x2) is the observed

I(x1) we want true source

PSF(x2-x1) instrument PSF

Question 5

this is the convolution of the distribution I with the PSF

Answer 5

O(x2) = I*PSF

Question 6

The FT of the convolution of two functions is equal to the multiplication of their FTs, i.e.

Answer 6

O = I * PSF
F(O) = F(I) x F(PSF)

Question 7

Can deconvolve via

Answer 7

I = F^(-1) [ F(0)/F(PSF) ]