Groups Flashcards

1
Q

Injective

A

one-to-one
(if f(x)=f(y) implies x=y for all x,y in A)

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2
Q

Surjective

A

all used or onto
(for any b in B, there exists a in A such that f(a)=b

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3
Q

Bijective

A

one-to-one and all used
(injective and surjective)

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4
Q

Group (G,*)

A

A set G together with a binary operation * such that:

1) is associative, meaning for a,b,c in G we have
(ab)c=a(bc).

2) there exists an identity element e such that for all a in G we have
ae=a=ea.

3) each element has an inverse, meaning for any g in G there exists g^(-1) in G such that
gg^(-1)=g^(-1)g.

Note: Check that it is a binary operation (for closure).

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5
Q

Sym(x)

A

Symmetric group on n letter denoted Sn

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6
Q

Permutations

A

Elements of Sn
(bijection or relabeling of those elements)

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7
Q

Function Composition

A

Product in S3
(applying one function to the results of another)

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8
Q

Cycle Notation

A

A permutation consisting of a single cycle. Example:
(1)(2)(3)
(12)(3)
(123)

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9
Q

a|b

A

notation for a divides b.
a|b if there exists x in the integers such that ax=b

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10
Q

a≅b mod m

A

If a and b are integers, we say that a is congruent to b modulo m if m|(a-b)

a is the same as b (up to) skip counting by m (not actually the same but the same answer; ex: mod 12 –> 1am and 1pm)

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11
Q

modulo

A

Two numbers are congruent modulo a given number if they give the same remainder when divided by that number.
Ex. 19 and 64 are congruent modulo 5

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12
Q

Theorem: Congruence as an Equivalence Relation

A

Let m be a positive integer. Congruence modulo m satisfies the following properties:

1) Reflexivity
2) Symmetry
3) Transitivity

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13
Q

Partitioning Integers

A

Define the congruence class of n mod m by:

[n]m:={a:a≅n mod m}

give one that does live there: n
ex. m=2:
[0]2 ={…,-6,-4,-2,0,2,4,6,…}
[6]2={…,-6,-4,-2,0,2,4,6,…}
[3]2={…,-5,-3,-1,1,3,5,…}

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14
Q

Least nonnegative residue

A

M is a positive integer. The division algorithm gives:

a=bm+r with 0 < or = r < or = m-1

We call the remainder (r) the least nonnegative residue of a modulo m

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15
Q

Theorem: Modular Arithmetic

A

Let a,b,c,d,m be integers with m>0, a≅b mod m and c≅d mod m
a+c ≅ b+d mod m [a+c]m=[b+d]m
a-c ≅ b-d mod m [a-c]m=[b-d]m
ac ≅ bd mod m [ac]m=[bd]m

Z/mZ:={[0]m,…,[m-1]m} where:
[a]m+[c]m= [a+c]m
[a]m-[c]m= [a-c]m
[a]m([c]m)= [ac]m

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16
Q
A