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General Science > Force And Pressure > Flashcards

Force And Pressure Flashcards

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1
Q

Strength of a force is expressed by its ?

A

Magnitude

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2
Q

Strength of a force is expressed by its ?

A

Magnitude

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3
Q

Strength of a force is expressed by its ?

A

Magnitude

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4
Q

State of motion of an object is described by its

A

Speed and direction of motion

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5
Q

State of motion of an object is described by its

A

Speed and direction of motion

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6
Q

Force responsible for changing the state of motion

A

Friction

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7
Q

Electrostatic force

A

Force exerted by charges body on another charged or incharged body

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8
Q

The weight of aur in a column of height of atm and area is as large as

A

10cm×10cm=1000kg

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9
Q

German sceuents of 17th century

A

Otto von guericke pumped air out of vessel , joined two mettalic hemispheres of 51 cn diameter each and then 8 horses to pull

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10
Q

Arrow striking due to

A

Gravity and friction and its state of motion is due to contact force

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11
Q

Dyne

A

G cm/s2

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12
Q

Dyne

A

G cm/s2

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13
Q

Newton

A

Kg m/s2

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14
Q

Acceleration

A

V(final velocity) - u(initial velocity)/time

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15
Q

V with an arrow

A

Velocity (magnitude +time)

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16
Q

V with an arrow

A

Velocity (magnitude +time)

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17
Q

Static charge

A

It’s remains stationary until it’s discharged (flow of electricity)

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18
Q

Mass is always positive?

A

Yes

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19
Q

Psi

A

Force of one pound force applied to an area of square inch

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20
Q

Standard atmospheric pressure at sea level

A

101325 pa

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21
Q

Tire inflating psi

A

32psi

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22
Q

Tire inflating psi

A

32psi

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23
Q

Altitude increase atm and density

A

Decreases

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24
Q

7 fundamental quantities in physics

A

Length , mass , time , electric current , temperature, amount of substance, luminous intensity

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25
Q

Scaler quantities

A

Mass , temperature, speed , distance, pressure

26
Q

Scaler quantities

A

Mass , temperature, speed , distance, pressure

27
Q

Vectors

A

Velocity , force , displacement, acceleration

28
Q

Vectors

A

Velocity , force , displacement, acceleration

29
Q

Gravitational force

A

G(constant ) m1m2(masses of 2 objects )/r2(distance between 2 masses)

30
Q

1 pa

A

1n/m2

31
Q

1 pa

A

1n/m2

32
Q

Bar

A

1 dyne /cm2

33
Q

Bar

A

1 dyne /cm2

34
Q

Air pressure is also known as

A

Biometric pressure

35
Q

Air pressure is also known as

A

Biometric pressure

36
Q

Atmospheric pressure? Pa? Atm? Mmhg

A

101320,1,760

37
Q

Atmospheric pressure? Pa? Atm? Mmhg

A

101320,1,760

38
Q

Fundamental force of nature

A

Gravity , electromagnetism , strong force , weak force

39
Q

Fundamental force of nature

A

Gravity , electromagnetism , strong force , weak force

40
Q

Strong force

A

Nucleii of atoms (nuclear force )

41
Q

Strong force

A

Nucleii of atoms (nuclear force )

42
Q

Weak force

A

Particles of matter are close to one another (van der walls force

43
Q

1 bar

A

105 pa

44
Q

1 bar

A

105 pa

45
Q

1 millibar

A

102 pa

46
Q

1 torr

A

133 pa

47
Q

Atmosphere extends upto

A

300kms

48
Q

Atmospheric pressure in pa

A

101.3 pa

49
Q

Balanced forces

A

Gravitational and muscular

50
Q

Forces acting on rocket

A

Gravitational and friction

51
Q

Forces acting on rocket

A

Gravitational and friction

52
Q

Tera

A

10 12

53
Q

Tera

A

10 12

54
Q

Giga
Mega
Kilo

A

9
6
5

55
Q

Milli
Micro
Nano
Pico
Femto

A

-3
6
9
12
15

56
Q

Alright, let’s start with one question:

Question 1:

A box with a mass of 50 kg is pushed with an acceleration of 3 m/s². What is the force applied to the box?

A

To find the force applied to the box, use Newton’s second law of motion:

[ F = m \times a ]

Given:
- ( m = 50 \, \text{kg} )
- ( a = 3 \, \text{m/s}^2 )

So,

[ F = 50 \, \text{kg} \times 3 \, \text{m/s}^2 = 150 \, \text{N} ]

The force applied to the box is 150 N.

57
Q

Alright, let’s start with one question:

Question 1:

A box with a mass of 50 kg is pushed with an acceleration of 3 m/s². What is the force applied to the box?

A

To find the force applied to the box, use Newton’s second law of motion:

[ F = m \times a ]

Given:
- ( m = 50 \, \text{kg} )
- ( a = 3 \, \text{m/s}^2 )

So,

[ F = 50 \, \text{kg} \times 3 \, \text{m/s}^2 = 150 \, \text{N} ]

The force applied to the box is 150 N.

58
Q

Question 2:

A force of 500 N is applied to an object, causing it to accelerate at 5 m/s². What is the mass of the object?

A

To find the mass of the object, use Newton’s second law of motion:

[ F = m \times a ]

Rearrange the formula to solve for mass ( m ):

[ m = \frac{F}{a} ]

Given:
- ( F = 500 \, \text{N} )
- ( a = 5 \, \text{m/s}^2 )

So,

[ m = \frac{500 \, \text{N}}{5 \, \text{m/s}^2} = 100 \, \text{kg} ]

The mass of the object is 100 kg.

59
Q

Question 2:

A force of 500 N is applied to an object, causing it to accelerate at 5 m/s². What is the mass of the object?

A

To find the mass of the object, use Newton’s second law of motion:

[ F = m \times a ]

Rearrange the formula to solve for mass ( m ):

[ m = \frac{F}{a} ]

Given:
- ( F = 500 \, \text{N} )
- ( a = 5 \, \text{m/s}^2 )

So,

[ m = \frac{500 \, \text{N}}{5 \, \text{m/s}^2} = 100 \, \text{kg} ]

The mass of the object is 100 kg.

60
Q

Question 3:

A book weighing 10 N rests on a table. If the area of the book in contact with the table is 0.02 m², what is the pressure exerted by the book on the table?

A

To find the pressure exerted by the book on the table, use the pressure formula:

[ P = \frac{F}{A} ]

Given:
- ( F = 10 \, \text{N} )
- ( A = 0.02 \, \text{m}^2 )

So,

[ P = \frac{10 \, \text{N}}{0.02 \, \text{m}^2} = 500 \, \text{Pa} ]

The pressure exerted by the book on the table is 500 Pa.

61
Q

Question 3:

A book weighing 10 N rests on a table. If the area of the book in contact with the table is 0.02 m², what is the pressure exerted by the book on the table?

A

To find the pressure exerted by the book on the table, use the pressure formula:

[ P = \frac{F}{A} ]

Given:
- ( F = 10 \, \text{N} )
- ( A = 0.02 \, \text{m}^2 )

So,

[ P = \frac{10 \, \text{N}}{0.02 \, \text{m}^2} = 500 \, \text{Pa} ]

The pressure exerted by the book on the table is 500 Pa.

62
Q

Question 4:

A tank with a base area of 2 m² contains water weighing 2000 N. What is the pressure exerted by the water on the base of the tank?

A

To find the pressure exerted by the water on the base of the tank, use the pressure formula:

[ P = \frac{F}{A} ]

Given:
- ( F = 2000 \, \text{N} )
- ( A = 2 \, \text{m}^2 )

So,

[ P = \frac{2000 \, \text{N}}{2 \, \text{m}^2} = 1000 \, \text{Pa} ]

The pressure exerted by the water on the base of the tank is 1000 Pa.

General Science (3 decks)

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