Experiment F1 Flashcards
Taking natural logarithms of equation (F1.2) gives
ln πΌ = ln πΌ0 β ππ₯.
β¬β¬βΊ Using equation (F1.2) and the definition of π₯1/2 show that
π₯1/2 = ln 2/π
ln πΌ =
ln πΌ = ln πΌ0 β ππ₯.
I =
Io exp (β ππ₯)
I =
Intensity of gamma ray
Io =
Initial absorption intensity
π =
Co-efficient of absorption of gamma ray
x =
Thickness
x1/2 =
Half value layer, is when : I = Io/2 β> x = x1/2
Way 1 of finding x1/2 from the experiments :
Way 2 of finding x1/2 from the experiments :
Way 3 of finding x1/2 from the experiments :
π·π bare =
π(π΄πΈ/π2)
A =
Ao exp (-Ξ»t)
Ξ» =
ln2/t1/2
n β‘ number of half value layers =
x/x1/2
factor =
(1/2)^π
Dose rate =
Drbar x factor x time
π·π shielded =
π·π bare Γ factor
π· =
π·π shielded Γ time